我已經創建了一個包含兩組複選框並希望將它們存儲在MySQL數據庫中的表單,但是當我發佈到數據庫時,所有數據都按照預期如日期,文本和單選按鈕,但兩個文本框除外。如果我查看數據庫中存儲文本框值的列,它只會顯示「數組」並且沒有任何實際值。如何將複選框中的多個值添加到mysql數據庫中
這是我的代碼來處理POST請求:
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$name = $_POST['input4'];
$datedone = $_POST['date'];
$projectnumber = $_POST['input1'];
$area = $_POST['input2'];
$donebefore = $_POST['radio9'];
$changesmade = $_POST['radio8'];
$safeaccess = $_POST['radio11'];
$electrical = $_POST['radio5'];
$machineguarding = $_POST['radio6'];
$correctequipment = $_POST['radio4'];
$sds = $_POST['radio3'];
$controltoxic = $_POST['radio1'];
$ppe = $_POST['radio2'];
$hazard = $_POST['checkbox'];
$otherhazards = $_POST['input3'];
$controlofhazards = $_POST['checkbox1'];
$monitor = $_POST['radio12'];
$comments = $_POST['input'];
$sql = "INSERT INTO hira (Name, TodayDate, ProjectNumber, Area, DoneBefore, HaveChangesMade, SafeAccess, ElectricalEquipment, MachineGuarding, CorrectEquipment, SDS, ControlToxic, PPE, Hazard, OtherHazard, ControlHazard, MonitorProcess, AdditionalComments) VALUES ('$name','$datedone','$projectnumber','$area','$donebefore','$changesmade','$safeaccess','$electrical','$machineguarding','$correctequipment','$sds','$controltoxic','$ppe','$hazard','$otherhazards','$controlofhazards','$monitor','$comments')";
if ($conn->query($sql) === TRUE) {
echo "Thank you for completing the Hira form";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
我做了什麼錯在這裏。我希望逗號分隔的文本框的值是「噪音,灰塵」 這是可能的嗎?提前
print_r $ _POST你會得到它,出了什麼問題,相信我 – rahulsm