如何在iPhone中將字符串轉換爲十六進制

Question

我是iPhone新手，我想將字符串轉換爲十六進制格式。

例如00A400024F01到0x00,0xA4,0x00,0x02,0x4F,0x01我想我應該先分開字符串，然後轉換分組值。我不知道該怎麼做。

Answer 1

ü從這個計算器的問題剛剛發現的答案： -

How to convert an NSString to hex values

+ (NSString *) stringToHex:(NSString *)str 
    { 
     NSUInteger len = [str length]; 
     unichar *chars = malloc(len * sizeof(unichar)); 
     [str getCharacters:chars]; 

     NSMutableString *hexString = [[NSMutableString alloc] init]; 

     for(NSUInteger i = 0; i < len; i++) 
     { 
      // [hexString [NSString stringWithFormat:@"%02x", chars[i]]]; /*previous input*/ 
      [hexString appendFormat:@"%02x", chars[i]]; /*EDITED PER COMMENT BELOW*/ 
     } 
     free(chars); 

     return [hexString autorelease]; 
    } 

UPDATE

您可以通過以下方法將一個刺兩個字符串： -

NSString * mystring = @"Hello,How are you";// suppos your string like that 
NSArray * array = [mystring componentsSeparatedByString:@","]; 
NSString * str1 = [array objectAtIndex:0]; //Hello 
NSString * str2 = [array objectAtIndex:1]; //How are you 

，如果你想murge兩個String在一個字符串，如： -

NSString *str1=@"hi Sweet Lady"; 
NSString *str2=@"How are you"; 

NSString *mainstr=[NSString stringWithFormat:@"%@ %@",str1,str2]; 

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