Python - 平等錯誤

Question

我有平等問題。以下代碼將嵌套列表與列表骰子進行比較。

def largeStraight(dice): 
    straightValues = [{1, 2, 3, 4, 5}, {2, 3, 4, 5, 6}] 
    return any(value.issubset(dice) for value in straightValues) 

def smallStraight(dice): 
    straightValues = [{1, 2, 3, 4}, {2, 3, 4, 5} , {3 ,4, 5, 6}] 
    return any(value.issubset(dice) for value in straightValues) 

def giveResult(dice): 
    score = 0 
    if(largeStraight): 
     score = 40 
    elif(smallStraight): 
     score = 30 
    else: 
     score = 0 
    return score 

dice = [1,2,3,4,1] 
print(giveResult(dice)) 

這應返回的30從giveResult的值，但是我得到一個分數的40

Answer 1

您需要通話您的功能：

def giveResult(dice): 
    score = 0 
    if largeStraight(dice): 
     score = 40 
    elif smallStraight(dice): 
     score = 30 
    else: 
     score = 0 
    return score 

只是指的是函數對象意味着你的第一個if將匹配，因爲大多數Python對象在布爾上下文中被認爲是真的。

您可以提前返回，簡化你的函數一點：

def giveResult(dice): 
    if largeStraight(dice): 
     return 40 
    if smallStraight(dice): 
     return 30 
    return 0 

Answer 2

你不傳遞任何進入你的方法：

def giveResult(dice): 
    score = 0 
    if(largeStraight(dice)): 
     score = 40 
    elif(smallStraight(dice)): 
     score = 30 
    else: 
     score = 0 
    return score