Python：獲取類的方法，屬於哪個方法

python類方法是否有方法/成員本身，它表示類，它們屬於？Python：獲取類的方法，屬於哪個方法

例如...：

# a simple global function dummy WITHOUT any class membership 
def global_function(): 
print('global_function') 

# a simple method dummy WITH a membership in a class 
class Clazz: 
def method(): 
    print('Clazz.method') 

global_function() # prints "global_function" 
Clazz.method() # prints "Clazz.method" 

# until here, everything should be clear 

# define a simple replacement 
def xxx(): 
print('xxx') 

# replaces a certain function OR method with the xxx-function above 
def replace_with_xxx(func, clazz = None): 
if clazz: 
    setattr(clazz, func.__name__, xxx) 
else: 
    func.__globals__[func.__name__] = xxx 

# make all methods/functions print "xxx" 
replace_with_xxx(global_function) 
replace_with_xxx(Clazz.method, Clazz) 

# works great: 
global_function() # prints "xxx" 
Clazz.method() # prints "xxx" 

# OK, everything fine! 
# But I would like to write something like: 
replace_with_xxx(Clazz.method) 
# instead of 
replace_with_xxx(Clazz.method, Clazz) 
# note: no second parameter Clazz!

現在我的問題是：怎麼可能，讓所有方法/函數調用印刷「XXX」，沒有「clazz中=無」的說法replace_with_xxx功能？？？

有什麼可能，如：

def replace_with_xxx(func): # before it was: (func, clazz = None) 
if func.has_class(): # something possible like this??? 
    setattr(func.get_class(), func.__name__, xxx) # and this ??? 
else: 
    func.__globals__[func.__name__] = xxx

非常感謝您的閱讀。我希望我能說清楚一點，我想要什麼。祝你今天愉快！ :)

來源

2011-01-29 kernel_logger

多麼可怕的想法。你爲什麼試圖修改一個類的結構？爲什麼不定義一個新班級？爲什麼不使用像** Strategy **這樣更簡單的設計模式？ – 2011-01-29 03:56:38