我怎麼能只顯示從Web服務的價值xml

我有下面的代碼，它從我的結果中得到一個字符串，但我試圖找到一種方式，只顯示我的xml服務的字符串的值，但我不能，如何僅顯示該值？在te代碼中，您只能看到Web服務的conexion，是否需要解析xml字符串？我怎麼能只顯示從Web服務的價值xml

--xml

<string xmlns="http://www.webserviceX.NET"> 
<?xml version="1.0" encoding="utf-16"?> 
<CurrentWeather> 
<Location>Mexico City/Licenci, Mexico (MMMX) 19-26N 099-06W</Location> 
<Time>Feb 09, 2016 - 11:44 AM EST/2016.02.09 1644 UTC</Time> 
<Wind> Calm:0</Wind> 
<Visibility> 7 mile(s):0</Visibility> 
<SkyConditions> mostly cloudy</SkyConditions> 
<Temperature> 51 F (11 C)</Temperature> 
<DewPoint> 30 F (-1 C)</DewPoint> 
<RelativeHumidity> 43%</RelativeHumidity> 
<Pressure> 30.47 in. Hg (1031 hPa)</Pressure> 
<Status>Success</Status> 
</CurrentWeather> 
</string>

public class UploadData { 
public String getWeather(String city,String country){ 
    String resultado = null; 
    SoapObject callWS; 
    callWS = new SoapObject("http://www.webserviceX.NET","GetWeather"); 
    callWS.addProperty("CityName", city); 
    callWS.addProperty("CountryName",country); 
    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); 
    envelope.bodyOut = callWS; 
    envelope.dotNet = true; 
    envelope.encodingStyle = SoapSerializationEnvelope.XSD; 
    HttpTransportSE androidHttpTranport = null; 
    try { 
     String conexion = "http://www.webservicex.com/globalweather.asmx?WSDL"; 
     androidHttpTranport = new HttpTransportSE(conexion); 
     androidHttpTranport.call("http://www.webserviceX.NET/GetWeather",envelope); 
     result = envelope.getResponse().toString(); 



    }catch (Exception e){ 
     System.out.println(e.getMessage()); 
     result=e.getMessage(); 
    } 
    return result; 
}}

來源

2016-02-09 lextonik

使用此行

result = (SoapObject) envelope.getResponse();

，而不是

result = envelope.getResponse().toString();

現在，如果您想訪問XML標記的某些值，則應該使用getProperty（）方法。請參閱文檔here。

舉例來說，你可以試試這個：

result.getProperty(1).toString();

來源

2016-02-09 19:02:10 nnunes10

我怎麼能只顯示從Web服務的價值xml

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