cython/numpy類型的數組

Question

我想構建一個python類型的int矩陣，一個64位有符號整數。

cdef matrix33(): 
    return np.zeros((3,3),dtype=int) 

cdef do_stuf(np.ndarray[int, ndim=2] matrix): 
    ... 
    return some_value 

def start(): 
    print do_stuf(matrix33()) 

它編譯正確的，但是當我運行它，我不斷收到此錯誤：

ValueError: Buffer dtype mismatch, expected 'int' but got 'long' 

我不能跟蟒蛇長的工作，但我不知道如何正確地轉換爲64 INT。

UPDATE

奧基。我很確定我正確使用了Cython。我寫的代碼是在capture go/atari去的遊戲中進行minmax搜索。

迄今爲止最調用的函數是這些：

cdef isThere_greedy_move(np.ndarray[np.int64_t, ndim=2]board, int player): 
    cdef int i, j 
    for i in xrange(len(board)): 
     for j in xrange(len(board)): 
      if board[i,j] == 0: 
       board[i,j] = player 
       if player in score(board): 
        board[i,j] = 0 
        return True 
       board[i,j] = 0 
    return False 


# main function of the scoring system. 
# returns list of players that eat a stone 
cdef score(np.ndarray[np.int64_t, ndim=2] board): 
    scores = [] 
    cdef int i,j 
    cdef np.ndarray[np.int64_t, ndim = 2] checked 
    checked = np.zeros((board.shape[0], board.shape[1]), dtype = int) 
    for i in xrange(len(board)): 
     for j in xrange(len(board)): 
      if checked[i,j] == 0 and board[i,j] !=0: 
       life, newly_checked = check_life(i,j,board,[]) 
       if not life: 
        if -board[i,j] not in scores: 
         scores.append(-board[i,j]) 
         if len(scores) == 2: 
          return scores 
       checked = update_checked(checked, newly_checked) 
    return scores 

# helper functions of score/1 
cdef check_life(int i, int j, np.ndarray[np.int64_t, ndim=2] board, checked): 
    checked.append((i,j)) 
    if liberty(i,j,board): 
     return True, checked 
    for pos in [[1,0],[0,1],[-1,0],[0,-1]]: 
     pos = np.array([i,j]) + np.array(pos) 
     if check_index(pos[0],pos[1],len(board)) and board[pos[0],pos[1]] == board[i,j] and (pos[0],pos[1]) not in checked: 
      life, newly_checked = check_life(pos[0],pos[1],board,checked) 
      if life: 
       checked = checked + newly_checked    
       return life, checked 
    return False, [] # [] is a dummy. 

cdef liberty(int i,int j, np.ndarray[np.int64_t, ndim=2] board): 
    for pos in [np.array([1,0]),np.array([0,1]),np.array([-1,0]),np.array([0,-1])]: 
     pos = np.array([i,j]) - pos 
     if check_index(pos[0],pos[1],len(board)) and board[pos[0],pos[1]] == 0: 
      return True 
    return False 

我真的認爲這將是照耀用Cython的機會。 爲了解決3x3的捕獲去：

的Python 2.7確實一致2.28秒，與用Cython它是一致的2.03 兩者都與蟒時間模塊和小於60℃°

一個i7處理器立即測試對我來說，問題是，如果我要切換到哈斯克爾或C++爲這個項目......

Answer 1

用Cython的int類型是一樣爲C int，即通常（但不一定）32位。你應該在聲明作爲matrix33的np.int64和dtype在do_stuf爲相應的C，np.int64_t：

cimport numpy as np 
import numpy as np 

cdef do_stuff(np.ndarray[np.int64_t, ndim=2] matrix): 
    pass 

cdef matrix33(): 
    return np.zeros((3,3), dtype=int) 

def start(): 
    print do_stuff(matrix33())