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我正在構建一個應用程序,拍攝一張照片,然後通過電子郵件發送。爲此,我必須將其保存到設備的內存中。我得到的問題是,當應用程序寫我的文件,它崩潰的代碼這一行:如何正確地將照片寫入內存並獲取URI(蜂窩)?
intent.putExtra(MediaStore.EXTRA_OUTPUT, Uri.fromFile(Environment.getExternalStorageDirectory()));
下你的整個功能和代碼:
private void takePicture(){
File outputFile = new File(Environment.getExternalStorageDirectory(), "image.jpg");
Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
intent.putExtra(MediaStore.EXTRA_OUTPUT, Uri.fromFile(Environment.getExternalStorageDirectory()));
startActivityForResult(intent, 1);
}
public void onActivityResult(int requestCode, int resultCode, Intent data){
if(requestCode == CAMERA_PIC_REQUEST && resultCode == Activity.RESULT_OK){
picture = (Bitmap) data.getExtras().get("data");
pictureView.setImageBitmap(picture);
ContentValues values = new ContentValues();
values.put(Images.Media.TITLE, "Picture");
values.put(Images.Media.BUCKET_ID, "picture_ID");
values.put(Images.Media.DESCRIPTION, "");
values.put(Images.Media.MIME_TYPE, "image/jpeg");
pictureUri = getContentResolver().insert(Media.EXTERNAL_CONTENT_URI, values);
OutputStream outstream;
try{
outstream = getContentResolver().openOutputStream(pictureUri);
picture.compress(Bitmap.CompressFormat.JPEG, 100, outstream);
outstream.close();
}catch(FileNotFoundException e){
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
如果我評論這一線,應用程序不會崩潰了。我需要獲取照片的URI,然後才能發送電子郵件。
任何幫助從你們更有經驗的那裏將不勝感激。