Hang子手 - 如何正確計數玩家錯誤的猜測？

Question

現在我的遊戲正確計算了我有多少正確的數字，但是如果不匹配字符的大小與字符串的長度相等，它就不會計數。我一直在嘗試修改這段代碼，但有一段時間它仍然無法修復。這裏是我的代碼：

/*includes and defines*/ 
    #include <stdio.h> 
    #include <string.h> 
    #define SIZE 50 

    /*prototype definitions*/ 
    int compareString(char *, char *); 

    int main(void){ 

     char word[SIZE]; 
     char input[SIZE]; 
     char guess[SIZE]; 
     int count = 0; 
     int wrong = 0; 
     int incorrect = 0; 
     int right = 0; 
     int len = 0; 

     printf("Please enter the word you would like to have to guess.\nThen hand your computer over to the person you would like to have play:"); 
     fgets(word, SIZE, stdin); 

     len = strlen(word); 

     printf("Please guess one letter for the %d letter word!\n", len - 1); 

     do{ 

      fgets(input, SIZE, stdin); 

      for(count = 0; count < len - 1; count++){ 
       if(input[0] == word[count]){ 
        printf("that letter is in the %d spot\n", count + 1); 
        ++right; 
       } 
       /*I know the problem lies here but i'm not sure how to fix it I've tried not using len-1   and just using len, I've tried not resetting the amount wrong. Everything!*/ 
       else if (input[0] != word[count]) { 
        ++wrong; 
         if(wrong == len - 1){ 
          ++incorrect; 
         } 
        wrong = 0; 
       } 
      } 

     }while(incorrect < 6 && right < len - 1); 


     return 0; 
    } 

我知道問題就出在這裏，代碼中設置播放器的錯誤。但我不知道如何解決它。我試過不使用len-1，只是使用len，我試過不重置錯誤的數量。

else if (input[0] != word[count]) { 
         ++wrong; 
          if(wrong == len - 1){ 
           ++incorrect; 
          } 
         wrong = 0; 
        } 

Answer 1

的問題是你想增加incorrect的方式。 只需使用wrong，如果你需要增加或不incorrect

在這裏，你會用它來決定一個布爾值，解決的辦法：

#include <stdio.h> 
#include <string.h> 
#define SIZE 50 

/*prototype definitions*/ 
int compareString(char *, char *); 

int main(void){ 

    char word[SIZE]; 
    char input[SIZE]; 
    char guess[SIZE]; 
    int count = 0; 
    int wrong = 1; 
    int incorrect = 0; 
    int right = 0; 
    int len = 0; 

    printf("Please enter the word you would like to have to guess.\nThen hand your computer over to the person you would like to have play:"); 
    fgets(word, SIZE, stdin); 

    len = strlen(word); 

    printf("Please guess one letter for the %d letter word!\n", len - 1); 

    do{ 

    fgets(input, SIZE, stdin); 
    wrong = 1; 
    for(count = 0; count < len - 1; count++){ 

     if(input[0] == word[count]){ 
     printf("that letter is in the %d spot\n", count + 1); 
     wrong = 0; 
     ++right; 
     } 
     /*I know the problem lies here but i'm not sure how to fix it I've tried not using len-1   and just using len, I've tried not resetting the amount wrong. Everything!*/ 
    } 
    if(wrong) { 
     incorrect++; 
    } 

    }while(incorrect < 6 && right < len - 1); 


    return 0; 
}