Q
選擇節點
1
A
回答
1
迭代通過切換,如果一個被發現含有相應的文本選擇切換更改爲節點:
private static Node[] fromStrings(ToggleGroup group, String... strings) {
Node[] result = new Node[strings.length];
for (int i = 0; i < strings.length; i++) {
ToggleButton button = new ToggleButton(strings[i]);
button.setPrefSize(100, 50);
button.setTextAlignment(TextAlignment.CENTER);
button.setToggleGroup(group);
result[i] = button;
}
return result;
}
@Override
public void start(Stage primaryStage) {
GridPane root = new GridPane();
final ToggleGroup group = new ToggleGroup();
root.addRow(0, fromStrings(group, "If", "VVS1", "VVS2", "VS1", "VS2", "SI1", "SI2", "SI2-", "SI3", "SI3-"));
root.addRow(1, fromStrings(group, "I1", "I1-", "I2", "I2-", "I3", "I4", "I5", "I6", "I7", "I8"));
root.setFocusTraversable(true);
root.setOnKeyTyped(new EventHandler<KeyEvent>() {
@Override
public void handle(KeyEvent event) {
String s = event.getCharacter().toUpperCase();
// move focus to the next matching element
if (s.length() == 1) {
event.consume();
List<Toggle> toggles = group.getToggles();
int selectedIndex = toggles.indexOf(group.getSelectedToggle());
int size = toggles.size();
// search next matching node starting directly after the
// selected position
for (int i = selectedIndex + 1; i < size; i++) {
Toggle l = toggles.get(i);
if (((Labeled)l).getText().toUpperCase().startsWith(s)) {
group.selectToggle(l);
return;
}
}
for (int i = 0; i < selectedIndex; i++) {
Toggle l = toggles.get(i);
if (((Labeled)l).getText().toUpperCase().startsWith(s)) {
group.selectToggle(l);
return;
}
}
}
}
});
Scene scene = new Scene(root);
root.requestFocus();
primaryStage.setScene(scene);
primaryStage.show();
}
0
我得到了答案。
@FXML
private AnchorPane acnCalc;
@FXML
private ToggleGroup grpClarity;
@FXML
private ToggleButton tglIf, tglVvs1, tglvvs2, tglVs1, tglVs2, tglSi1, tglSi2, tglSi22, tglSi3, tglSi32, tglI1,
tglI12, tglI2, tglI22, tglI3, tglI4, tglI5, tglI6, tglI7, tglI8;
我已經使用場景構建器將切換組設置爲所有切換按鈕。
public void initialize(URL location, ResourceBundle resources) {
HashMap<String, ToggleButton> lstCalc = new HashMap<>();
for (Toggle t : grpClarity.getToggles()) {
ToggleButton chk = (ToggleButton) t;
lstCalc.put(chk.getText(), chk);
}
acnCalc.setOnKeyPressed(new EventHandler<KeyEvent>() {
@Override
public void handle(KeyEvent ke) {
if (ke.getCode().equals(KeyCode.I)) {
if (lstCalc.get("If").isFocused()) {
lstCalc.get("I1").requestFocus();
} else if (lstCalc.get("I1").isFocused()) {
lstCalc.get("I1-").requestFocus();
} else if (lstCalc.get("I1-").isFocused()) {
lstCalc.get("I2").requestFocus();
} else if (lstCalc.get("I2").isFocused()) {
lstCalc.get("I2-").requestFocus();
} else if (lstCalc.get("I2-").isFocused()) {
lstCalc.get("I3").requestFocus();
} else if (lstCalc.get("I3").isFocused()) {
lstCalc.get("I4").requestFocus();
} else if (lstCalc.get("I4").isFocused()) {
lstCalc.get("I5").requestFocus();
} else if (lstCalc.get("I5").isFocused()) {
lstCalc.get("I6").requestFocus();
} else if (lstCalc.get("I6").isFocused()) {
lstCalc.get("I7").requestFocus();
} else if (lstCalc.get("I7").isFocused()) {
lstCalc.get("I8").requestFocus();
}
else {
lstCalc.get("If").requestFocus();
}
}
if (ke.getCode().equals(KeyCode.S)) {
if (lstCalc.get("SI1").isFocused()) {
lstCalc.get("SI2").requestFocus();
} else if (lstCalc.get("SI2").isFocused()) {
lstCalc.get("SI2-").requestFocus();
} else if (lstCalc.get("SI2-").isFocused()) {
lstCalc.get("SI3").requestFocus();
} else if (lstCalc.get("SI3").isFocused()) {
lstCalc.get("SI3-").requestFocus();
}
else {
lstCalc.get("SI1").requestFocus();
}
}
if (ke.getCode().equals(KeyCode.V)) {
if (lstCalc.get("VVS1").isFocused()) {
lstCalc.get("VVS2").requestFocus();
} else if (lstCalc.get("VVS2").isFocused()) {
lstCalc.get("VS1").requestFocus();
} else if (lstCalc.get("VS1").isFocused()) {
lstCalc.get("VS2").requestFocus();
}
else {
lstCalc.get("VVS1").requestFocus();
}
}
}
}
}
+0
這是工作太多,但不同類型的邏輯.... – CTN
+1
兩個答案在工作中..! – 2016-10-25 08:29:40
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感謝您的回答... 它對我而言... – CTN