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這是我login.java 我要讓服務器註冊在Android如何在android中向服務器發送註冊數據?
public class Login extends Activity implements OnClickListener{
\t
\t private EditText name,lastName,phoneNumber;
\t private Button reg_btn;
\t private ProgressDialog pDialog;
\t JSONParser jsonParser = new JSONParser();
\t private static final String LOGIN_URL = "http://mojtabaapp.esy.es/register.php";
\t private static final String TAG_SUCCESS = "success";
\t private static final String TAG_MESSAGE = "message";
\t
\t
\t
\t @Override
\t protected void onCreate(Bundle savedInstanceState) {
\t \t super.onCreate(savedInstanceState);
\t \t setContentView(R.layout.activity_login);
\t \t
\t \t // tarif ha
\t \t name=(EditText)findViewById(R.id.ET_name);
\t \t lastName=(EditText)findViewById(R.id.ET_famili);
\t \t phoneNumber=(EditText)findViewById(R.id.ET_phone);
\t \t reg_btn=(Button)findViewById(R.id.reg_btn);
\t \t
\t \t reg_btn.setOnClickListener(this);
\t \t
\t \t
\t }
\t
\t @Override
\t public void onClick(View v) {
\t \t // TODO Auto-generated method stub
\t \t
\t \t \t \t new CreateUser().execute();
\t \t
\t }
\t
\t class CreateUser extends AsyncTask<String, String, String> {
\t \t
boolean failure = false;
\t \t
@Override
protected void onPreExecute() {
super.onPreExecute();
pDialog = new ProgressDialog(Login.this);
pDialog.setMessage("..لطفا کمی صبر کنید");
pDialog.setIndeterminate(false);
pDialog.setCancelable(true);
pDialog.show();
}
\t \t
\t \t @Override
\t \t protected String doInBackground(String... args){
\t \t \t
\t \t \t // TODO Auto-generated method stub
\t \t \t // Check for success tag
int success;
String NAME = name.getText().toString();
String LASTNAME = lastName.getText().toString();
String PHONE=phoneNumber.getText().toString();
try {
// Building Parameters
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("username", NAME));
params.add(new BasicNameValuePair("password", LASTNAME));
params.add(new BasicNameValuePair("phone", PHONE));
Log.d("request!", "starting");
//Posting user data to script
JSONObject json = jsonParser.makeHttpRequest(
LOGIN_URL, "POST", params);
// full json response
Log.d("Login attempt", json.toString());
// json success element
success = json.getInt(TAG_SUCCESS);
if (success == 1) {
\t Log.d("User Created!", json.toString()); \t
\t finish();
\t return json.getString(TAG_MESSAGE);
}else{
\t Log.d("Login Failure!", json.getString(TAG_MESSAGE));
\t return json.getString(TAG_MESSAGE);
\t
}
} catch (JSONException e) {
e.printStackTrace();
}
return null;
\t
\t \t \t
\t \t }
\t \t
\t \t protected void onPostExecute(String file_url) {
\t // dismiss the dialog once product deleted
\t pDialog.dismiss();
\t if (file_url != null){
\t \t Toast.makeText(Login.this, file_url, Toast.LENGTH_LONG).show();
\t }
\t
\t }
}
\t @Override
\t public boolean onCreateOptionsMenu(Menu menu) {
\t \t // Inflate the menu; this adds items to the action bar if it is present.
\t \t getMenuInflater().inflate(R.menu.login, menu);
\t \t return true;
\t }
\t @Override
\t public boolean onOptionsItemSelected(MenuItem item) {
\t \t // Handle action bar item clicks here. The action bar will
\t \t // automatically handle clicks on the Home/Up button, so long
\t \t // as you specify a parent activity in AndroidManifest.xml.
\t \t int id = item.getItemId();
\t \t if (id == R.id.action_settings) {
\t \t \t return true;
\t \t }
\t \t return super.onOptionsItemSelected(item);
\t }
}
這就是我的Java代碼
<?php
require("config.inc.php");
if (!empty($_POST)) {
if (empty($_POST['username']) || empty($_POST['password']) || empty($_POST['phone'])) {
$response["success"] = 0;
$response["message"] = "error";
die(json_encode($response));
}
$query = " SELECT 1 FROM users WHERE username = :user";
$query_params = array(
':user' => $_POST['username']
);
try {
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch (PDOException $ex) {
$response["success"] = 0;
$response["message"] = "Error";
die(json_encode($response));
}
$row = $stmt->fetch();
if ($row) {
$response["success"] = 0;
$response["message"] = "I'm sorry, this username is already in use";
die(json_encode($response));
}
$query = "INSERT INTO users (username, password , phone) VALUES (:user, :pass , :phonenumber) ";
$query_params = array(
':user' => $_POST['username'],
':pass' => $_POST['password'],
':phonenumber' => $_POST['phone']
);
//time to run our query, and create the user
try {
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch (PDOException $ex) {
// For testing, you could use a die and message.
//die("Failed to run query: " . $ex->getMessage());
//or just use this use this one:
$response["success"] = 0;
$response["message"] = "Database Error2. Please Try Again!";
die(json_encode($response));
}
$response["success"] = 1;
$response["message"] = "Username Successfully Added!";
echo json_encode($response);
} else {
?>
\t <h1>Register</h1>
\t <form action="register.php" method="post">
\t Username:<br />
\t <input type="text" name="username" value="" />
\t <br /><br />
\t Password:<br />
\t <input type="password" name="password" value="" />
\t <br /><br />
\t <input type="submit" value="Register New User" />
\t </form>
\t <?php
}
?>
這是我的。主機上的PHP代碼
,但我的應用程序要forcestop這樣 請幫我 哪裏是我的問題
我對數據庫 用戶名密碼 ID 手機
在您的doInBackground()方法中,您打電話給\t finish();我相當肯定會結束你的活動。如果需要幫助診斷問題,則需要發佈堆棧跟蹤。 –