試圖加入兩個表格，並顯示正確的信息

Question

@followers = current_user.followers.joins(:received_messages).uniq.order("id DESC") 

快速解釋，它抓住當前用戶的關注者，並將它們與消息一起發送/接收。並且一次只顯示一個。

我用這個來顯示收件箱中的'消息'部分工作正常，我想通過最新發送或收到的消息ID訂購該收件箱。

現在我的看法是這樣的，（這是一個混亂的地獄，我知道有一些辦法，我做清潔的紅寶石）

-if f.sent_messages.first && f.received_messages.first 
    -if f.sent_messages.last.id > f.received_messages.last.id 
    p This is running 
    =image_tag f.avatar 
    h2= f.uid 
    p= f.sent_messages.last.body 
    =link_to "Go To Conversation", conversation_path(:id => f.sent_messages.last.sender_id) 
    -else 
    =image_tag f.avatar 
    h2= f.uid 
    p= f.received_messages.last.body 
    =link_to "Go To Conversation", conversation_path(:id => f.received_messages.last.receiver_id) 
    end 
-elsif f.sent_messages.first && f.received_messages.first == nil 
    =image_tag f.avatar 
    h2= f.uid 
    p= f.sent_messages.last.body 
    =link_to "Go To Conversation", conversation_path(:id => f.sent_messages.last.sender_id) 
-elsif f.sent_messages.first == nil && f.received_messages.first 
    =image_tag f.avatar 
    h2= f.uid 
    p= f.received_messages.last.body 
    =link_to "Go To Conversation", conversation_path(:id => f.received_messages.last.receiver_id) 

Answer 1

試試這個

-if f.sent_messages.any? || f.received_messages.any? 
    =image_tag f.avatar 
    %h2 = f.uid 
    -unless f.sent_messages.empty? || f.received_messages.empty? 
    -message,id = f.sent_messages.last.id > f.received_messages.last.id ? [f.sent_messages.last,f.sent_messages.last.sender_id] : [f.received_messages.last, f.received_messages.last.receiver_id] 
    -else 
    -message,id = f.sent_messages.last.nil? ? [f.received_messages.last,f.received_messages.last.receiver_id] : [f.sent_messages.last,f.sent_messages.last.sender_id] 
    %p = message.body 
    =link_to "Go To Conversation", conversation_path(:id => id)