排序陣列由第一子陣列

Question

多維我有一個數組，我想對它進行排序：

$ArrayStock = array(array("SIZE","L","XL","M"),("STOCK","12","3","2")); 

我怎樣才能通過「大小」數組排序？

或者，我可以用這個數組爲出發點：

$ArrayStock = array(array("L","XL","M"),("12","3","2")); 

Answer 1

將有幾種方法來剝皮這隻貓。我所有的方法會產生預期的輸出...

首先，讓我們做沒有重組的陣列（Demo）：

$order=["XS","S","M","L","XL","2XL","3XL"]; // declare appropriate size order 
$ArrayStock=[["L","XL","M"],["12","3","2"]]; 

// Order the first subarray: 
uasort($ArrayStock[0],function($a,$b)use($order){ 
    return (array_search($a,$order)>array_search($b,$order)?1:-1); // any unidentifed sizes will go to the front 
}); 

// Sync the second subarray with first subarray: 
$ArrayStock[1]=array_replace($ArrayStock[0],$ArrayStock[1]); 

// Optionally re-index the keys: 
$ArrayStock[0]=array_values($ArrayStock[0]); 
$ArrayStock[1]=array_values($ArrayStock[1]); 

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接下來，我將展示的幾種方法你可以操縱一個重組數組。 trincot編寫他的方式絕對沒有錯。這些只是我已經提出的替代方案...

我同意trincot關於使用尺寸作爲關鍵字（因爲它們將是唯一的）和股票作爲價值計數。因此，第一個過程是生成新的數組結構：

$ArrayStock=[["L","XL","M"],["12","3","2"]]; 

＃1一襯墊array_combine()的方法：

$new_structure=array_combine($ArrayStock[0],$ArrayStock[1]); 
// $new_structure = ['L'=>'12','XL'=>'3','M'=>'2'] 

＃2foreach()方法：

foreach($ArrayStock[0] as $i=>$size){ 
    $new_structure[$size]=$ArrayStock[1][$i]; 
} 
// $new_structure = ['L'=>'12','XL'=>'3','M'=>'2'] 

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現在到了新的數組排序，你可以使用uksort()或者一系列其他陣列功能與預定的順序排列/循環：

$order=["XS","S","M","L","XL","2XL","3XL"]; // declare whatever appropriate sizes in order 

＃1uksort()與array_search()方法：

uksort($new_structure,function($a,$b)use($order){ 
    return (array_search($a,$order)>array_search($b,$order)?1:-1); 
    // any unidentified sizes will go to the front of the array 
}); 
// keep in mind, this doesn't declare $result, it sorts $new_structure 

＃2array_replace()與array_flip() - array_intersect() - array_keys()方法：

$result=array_replace(      // replace values on matching keys 
      array_flip(      // swap keys with values 
       array_intersect(
        $order,     // keep values from here 
        array_keys($new_structure) // that exist here 
       ) 
      ), 
     $new_structure);      // use these elements for replace 
// $result=['M'=>'2','L'=>'12','XL'=>'3']; 

＃3foreach()與array_intersect() - array_keys()方法：

// generate & iterate ordered array 
foreach(array_intersect($order,array_keys($new_structure)) as $v){ 
    $result[$v]=$new_structure[$v];  // build properly sorted array 
} 
// $result=['M'=>'2','L'=>'12','XL'=>'3']; 

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最後的trincot已經表明，你可以恢復排序的數據恢復到初始格式多一個單襯裏：

$ArrayStock=[array_keys($result),array_values($result)]; 

Answer 2

你可以做這樣的：

// Combine into one associative array 
$combined = array_combine($ArrayStock[0], $ArrayStock[1]); 

// Rebuild it in the correct order: 
foreach(["SIZE", "S","M","L","XL","XXL"] as $size) { 
    if (isset($combined[$size])) $result[$size] = $combined[$size]; 
} 

// Split associative array back to its original structure: 
$ArrayStock = [array_keys($result), array_values($result)]; 

注意，這種結構是不是在它的使用如此的實用。實際上我會堅持使用關聯數組。