轉換JSON對象數組屬性的值的列表中angularjs

Question

我有對象的此列表 -

var o_list = [{id:1,name:jo},{id:2,name:mo}];

和我想提取這樣的事情 -

變種列表= [1,2 ]

有什麼已經建成的，或者我們該如何實現這一點。

Answer 1

您可以只映射它

var o_list = [{id:1,name:"jo"},{id:2,name:"mo"}]; 
 

 
var list = o_list.map(x => x.id); 
 

 
document.body.innerHTML = '<pre>' + JSON.stringify(list, 0, 4) + '</pre>';

Answer 2

，你可以做到這一點使用過濾器 https://docs.angularjs.org/api/ng/filter/filter

var myApp = angular.module('myApp', []); 
 

 
myApp.controller("myCtrl", ['$scope', '$filter', 
 
    function($scope, $filter) { 
 
    $scope.values = [{ 
 
     id: 1, 
 
     name: 'asdas' 
 
    }, { 
 
     id: 2, 
 
     name: 'blabla' 
 
    }]; 
 
    
 
    // this is how you use filters in your script 
 
    console.log($filter('extract')($scope.values)); 
 
    } 
 
]); 
 

 
myApp.filter('extract', function() { 
 
    return function(input) { 
 
    return input.map(x => x.id); 
 
    } 
 
});

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script> 
 
<div ng-app="myApp"> 
 
    <div ng-controller="myCtrl"> 
 
    <ol ng-repeat="id in values | extract"> 
 
     <li ng-bind="id"></li> 
 
    </ol> 
 
    </div> 
 
</div>

Answer 3

只能使用javscript forEach陣列的方法，從而獲得所需結果

var o_list = [{id:1,name:'jo'},{id:2,name:'mo'}]; 

var list =[]; 
o_list.forEach(function(item){ 
list.push(item.id) 

}) 

console.log(list) 

JSFIDDLE

Answer 4

var o_list = [{id:1,name:jo},{id:2,name:mo}]; 
var list = []; 

for(i = 0; i < o_list.length; i++){ 
    list.push(o_list[i].id); 
} 

Answer 5

你可以使用這個簡單的for循環

var o_list = [{id:1,name:'jo'},{id:2,name:'mo'}]; 
var s=[]; 
for (var i=0;i< o_list.length;i++){ 
s.push(o_list[i].id); 

} 

Answer 6

替代你可以使用underscore.js每種方法得到結果

 var o_list = [{id:1,name:'jo'},{id:2,name:'mo'}]; 

     var list =[]; 
     _.each(o_list, function(d){ 
         list.push(d.id) 
         });