十進制值四捨五入到ios中的下一個更高值

Question

在我的應用程序中，接受金額值（float）並保存它。在金額字段中，用戶可以在小數點後輸入任意數量的數字。但是，當我讀取並保存時，它應該只有小數點後的兩位數。這個場景適用於我的代碼。但問題是，如果用戶輸入值2.468，它將被保存爲2.47。但如果用戶輸入是2.245，在這種情況下，我需要保存爲2.25，但它只能保存爲2.24。

和我的代碼是

AmountValue = [NSString stringWithFormat:@"%f",[AmountTxt1.text floatValue]]; 
float Rate_int = [AmountValue floatValue]; 

NSNumberFormatter *currencyFormatter = [[NSNumberFormatter alloc] init]; 
[currencyFormatter setNumberStyle:NSNumberFormatterCurrencyStyle]; 
NSString *str1 = [NSString stringWithFormat:@"%@",[currencyFormatter stringFromNumber:[NSNumber numberWithFloat:Rate_int]]]; 

TotalAmtTxt.text = str1; 

Answer 1

double Rate_int1 = [input doubleValue]; 

NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init]; 
[formatter setNumberStyle:NSNumberFormatterDecimalStyle]; 
[formatter setRoundingMode: NSNumberFormatterRoundHalfUp]; 
[formatter setMaximumFractionDigits:2]; 

NSString *numberString = [formatter stringFromNumber:[NSNumber numberWithDouble:Rate_int1]]; 

NSString的numberString根據您的2.243將是什麼輸出具有四捨五入值..

Answer 2

試試這個代碼..

NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init]; 
[formatter setNumberStyle:NSNumberFormatterDecimalStyle]; 
[formatter setMaximumFractionDigits:2]; 
[formatter setRoundingMode: NSNumberFormatterRoundHalfUp]; 

NSString *numberString = [formatter stringFromNumber:[NSNumber numberWithFloat:Rate_int]]; 

TotalAmt.txt = numberString; 

Answer 3

你添加以下代碼：

[currencyFormatter setNumberStyle:NSNumberFormatterDecimalStyle]; 
[currencyFormatter setRoundingMode:NSNumberFormatterRoundHalfUp]; 
[currencyFormatter setMaximumFractionDigits:2]; 

NSLog(@"%@",[currencyFormatter stringFromNumber:[NSNumber numberWithDouble:2.245]]); 

Answer 4

float a=2.245; 
float b=ceilf(a*100)/100; 

或

NSNumberFormatter *currencyFormatter = [[NSNumberFormatter alloc] init]; 
    [currencyFormatter setNumberStyle:NSNumberFormatterDecimalStyle]; 
    [currencyFormatter setRoundingMode:NSNumberFormatterRoundCeiling]; 
    [currencyFormatter setMaximumFractionDigits:2];