按字母順序獲取所有歌曲的專輯列表

Question

這裏是我寫的代碼，錯誤是getContentResolver().query(MediaStore.Audio.Media.Album.EXTERNAL_CONTENT_URI, proj, null, null, null)有錯誤，無法解析專輯。這是獲得專輯列表的正確方式還是有其他更好的方法？我想要做的流派一樣，藝術家所以如果他們以不同的方式，請告訴它：

public class AlbumsFragment extends Fragment{ 
public AlbumsFragment() {} 
@Override 
public void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
} 

@Override 
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) { 
    View view=inflater.inflate(R.layout.fragment_albums, container, false); 
    ListView albumView=(ListView)view.findViewById(R.id.albumsView); 
    ArrayList<String> albumList = new ArrayList<>(); 
    String[] proj = {MediaStore.Audio.Media.ALBUM}; 
    final Cursor albumCursor = getActivity().getContentResolver().query(MediaStore.Audio.Media.Album.EXTERNAL_CONTENT_URI, proj, null, null, null); 

    if (albumCursor != null) { 
     if (albumCursor.moveToFirst()) { 
      do { 
       int albumIndex = albumCursor.getColumnIndexOrThrow(MediaStore.Audio.Media.ALBUM); 
       albumList.add(albumCursor.getString(albumIndex)); 
      } while (albumCursor.moveToNext()); 
     } 
    } 
    albumCursor.close(); 
    return view; 
      } 

}

Answer 1

代碼將是

您應該查詢像相冊這

String[] projection = new String[] { Albums._ID, Albums.ALBUM, Albums.ARTIST, Albums.ALBUM_ART, Albums.NUMBER_OF_SONGS }; 
String selection = null; 
String[] selectionArgs = null; 
String sortOrder = Media.ALBUM + " COLLATE NOCASE ASC"; 
Cursor cursor = contentResolver.query(Albums.EXTERNAL_CONTENT_URI, projection, selection, selectionArgs, sortOrder);