我試圖對用戶提交的地址進行地理編碼並將其存儲到數據庫中。表單調用一個php文件,其中javascript檢索地址並對其進行地理編碼。然後lat和lng值被傳遞給php並存儲在數據庫中,但是數據庫中唯一的值是零。將變量從html傳遞到javascript到php
HTML文件:
<html>
<body>
<form action="registerEvent.php" id="form" method="post">
<input id="address" name="address" placeholder="Adrese" type="text">
<button type="submit" id="submit">Send</button>
</form>
</body>
</html>
registerEvent.php:
<script src="https://maps.googleapis.com/maps/api/js?v=3.exp&signed_in=true"></script>
<script>
var geocoder;
var inputLat;
var inputLng;
function codeAddress() {
geocoder = new google.maps.Geocoder();
var address = document.getElementById('address').value;
geocoder.geocode({ 'address': address}, function(results, status) {
if (status == google.maps.GeocoderStatus.OK) {
var inputLat = event.latLng.lat();
var inputLng = event.latLng.lng();
} else {
alert('Geocode was not successful for the following reason: ' + status);
}
});
}
function passvariable() {
window.location.href = "registerEvent.php?lat=" + inputLat;
window.location.href = "registerEvent.php?lng=" + inputLng;
}
codeAddress();
passvariable();
</script>
<?php
require("dbinfo.php");
$connection=mysqli_connect ('localhost', $username, $password);
if (!$connection) {
die('Not connected : ' . mysql_error());
}
$db_selected = mysqli_select_db($connection, $database);
if (!$db_selected) {
die ('Can\'t use db : ' . mysql_error());
}
$lat =$_GET['inputLat'];
$lng =$_GET['inputLng'];
$sql = "INSERT INTO sometable (lat, lng)
VALUES ('$lat', '$lng')";
if (!mysqli_query($connection,$sql)) {
die('Error: ' . mysqli_error($connection));
};
mysqli_close($connection);
?>
我認爲HTML文件是一個單獨的文件和registerEvent.php顯示重定向到自身的JavaScript,它然後保存 – cornelb