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我捕獲錯誤,不知道如何解決它。我正在爲可用的SQLDrivers(提供者)進行組合框選擇器。的Qt的QList <T>鑄件和node_copy
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#include "QObject"
#include "QString"
#include "QList"
#include "QPointer"
class TProvider;
typedef const TProvider * const TProviderPointer;
class TProvider
{
public:
QString name;
QString driverName;
TProvider(QString name, QString driverName);
static const QList<TProviderPointer> getAvailableProviders();
static TProviderPointer getProvider(int id);
};
TProviderPointer MySQLProvider = new TProvider("MySQL", "QMYSQL");
TProviderPointer IBProvider = new TProvider("Interbase", "QIBASE");
CPP。在這裏,我創建了兩個常量指針給常量提供者(TProviderPointer)(枚舉可用驅動程序)。我有一個方法,返回const QList。
#include "tprovider.h"
TProvider::TProvider(QString name, QString driverName):
name(name), driverName(driverName)
{
}
const QList<TProviderPointer> TProvider::getAvailableProviders()
{
QList<TProviderPointer> list;
list.append(MySQLProvider);
list.append(IBProvider);
return list;
}
TProviderPointer getProvider(int id)
{
switch(id){
case 0:
return MySQLProvider;
case 1:
return IBProvider;
}
}
當我使用這個
const QList<TProviderPointer> list = TProvider::getAvailableProviders();
foreach (TProviderPointer provider, list) {
ui->eprovider->addItem(provider->name);
}
我得到和錯誤指向qlist.h和線路const QList<TProviderPointer> list = TProvider::getAvailableProviders();
- > C2440 TProviderPointer *
到void *
行:
Q_INLINE_TEMPLATE void QList<T>::node_copy(Node *from, Node *to, Node *src)
我是否有任何副本使用中的操作?我怎樣才能解決這個問題? 謝謝。