我正在創建一個紙牌遊戲,一個頁面創建遊戲並將每個玩家的所有紙牌插入到MySQL數據庫中。 c1,c2,c3 ...等是由您選擇的隨機卡存儲的。高級數組排序PHP
因此,card1將以c1的形式存儲在數據庫中,其餘12張卡片將作爲c1存儲在數據庫中。
但
後的卡從DATABSE返回遊戲頁面上,他們通過一系列與卡中的圖片進行組織。然後通過兩個數組顯示它們。
echo '<form input="index.php" method="post">';
echo $cards[$fetch['c1']].'<input class="check" type="checkbox" name="c1c">';
echo $cards[$fetch['c2']].'<input class="check" type="checkbox" name="c2c">';
echo $cards[$fetch['c3']].'<input class="check" type="checkbox" name="c3c">';
echo $cards[$fetch['c4']].'<input class="check" type="checkbox" name="c4c">';
echo $cards[$fetch['c5']].'<input class="check" type="checkbox" name="c5c">';
echo $cards[$fetch['c6']].'<input class="check" type="checkbox" name="c6c">';
echo $cards[$fetch['c7']].'<input class="check" type="checkbox" name="c7c">';
echo $cards[$fetch['c8']].'<input class="check" type="checkbox" name="c8c">';
echo $cards[$fetch['c9']].'<input class="check" type="checkbox" name="c9c">';
echo $cards[$fetch['c10']].'<input class="check" type="checkbox" name="c10c">';
echo $cards[$fetch['c11']].'<input class="check" type="checkbox" name="c11c">';
echo $cards[$fetch['c12']].'<input class="check" type="checkbox" name="c12c">';
echo $cards[$fetch['c13']].'<input class="check" type="checkbox" name="c13c">';
print_r($fetch);
$cards
是圖片分類器。
$fetch
是從數據庫返回的數組。
$query = "SELECT c1,c2,c3,c4,c5,c6,c7,c8,c9,c10,c11,c12,c13 FROM games WHERE comp = 0";
$stmt = $db->prepare($query);
$stmt->execute();
$fetch = $stmt->fetch(PDO::FETCH_ASSOC);
asort($fetch);
下面這段代碼爲我提供了正是我需要的print_r
回報
Array ([c9] => 3 [c5] => 6 [c10] => 8 [c11] => 13 [c13] => 15 [c3] => 16 [c2] => 18 [c1] => 19 [c4] => 24 [c8] => 40 [c12] => 44 [c7] => 45 [c6] => 47)
有組織的上升,但後來當我顯示卡,我無法弄清楚如何讓他們的順序運行,因爲關鍵是數據庫中的列名,以及我在顯示中無法要求的值。
所以我的基本問題是,我如何排序卡,以便他們運行通過我當前的陣列中排序圖片升序卡?
如果需要;
$cards = array(
"0" => "<img src=\"cards/dead.png\"/>",
"1" => "<img src=\"cards/2_of_spades.png\"/>",
"2" => "<img src=\"cards/3_of_spades.png\"/>",
"3" => "<img src=\"cards/4_of_spades.png\"/>",
"4" => "<img src=\"cards/5_of_spades.png\"/>",
"5" => "<img src=\"cards/6_of_spades.png\"/>",
"6" => "<img src=\"cards/7_of_spades.png\"/>",
"7" => "<img src=\"cards/8_of_spades.png\"/>",
"8" => "<img src=\"cards/9_of_spades.png\"/>",
"9" => "<img src=\"cards/10_of_spades.png\"/>",
"10" => "<img src=\"cards/jack_of_spades2.png\"/>",
"11" => "<img src=\"cards/queen_of_spades2.png\"/>",
"12" => "<img src=\"cards/king_of_spades2.png\"/>",
"13" => "<img src=\"cards/ace_of_spades.png\"/>",
"14" => "<img src=\"cards/2_of_clubs.png\"/>",
"15" => "<img src=\"cards/3_of_clubs.png\"/>",
"16" => "<img src=\"cards/4_of_clubs.png\"/>",
"17" => "<img src=\"cards/5_of_clubs.png\"/>",
"18" => "<img src=\"cards/6_of_clubs.png\"/>",
"19" => "<img src=\"cards/7_of_clubs.png\"/>",
"20" => "<img src=\"cards/8_of_clubs.png\"/>",
"21" => "<img src=\"cards/9_of_clubs.png\"/>",
"22" => "<img src=\"cards/10_of_clubs.png\"/>",
"23" => "<img src=\"cards/jack_of_clubs2.png\"/>",
"24" => "<img src=\"cards/queen_of_clubs2.png\"/>",
"25" => "<img src=\"cards/king_of_clubs2.png\"/>",
"26" => "<img src=\"cards/ace_of_clubs.png\"/>",
"27" => "<img src=\"cards/2_of_hearts.png\"/>",
"28" => "<img src=\"cards/3_of_hearts.png\"/>",
"29" => "<img src=\"cards/4_of_hearts.png\"/>",
"30" => "<img src=\"cards/5_of_hearts.png\"/>",
"31" => "<img src=\"cards/6_of_hearts.png\"/>",
"32" => "<img src=\"cards/7_of_hearts.png\"/>",
"33" => "<img src=\"cards/8_of_hearts.png\"/>",
"34" => "<img src=\"cards/9_of_hearts.png\"/>",
"35" => "<img src=\"cards/10_of_hearts.png\"/>",
"36" => "<img src=\"cards/jack_of_hearts2.png\"/>",
"37" => "<img src=\"cards/queen_of_hearts2.png\"/>",
"38" => "<img src=\"cards/king_of_hearts2.png\"/>",
"39" => "<img src=\"cards/ace_of_hearts.png\"/>",
"40" => "<img src=\"cards/2_of_diamonds.png\"/>",
"41" => "<img src=\"cards/3_of_diamonds.png\"/>",
"42" => "<img src=\"cards/4_of_diamonds.png\"/>",
"43" => "<img src=\"cards/5_of_diamonds.png\"/>",
"44" => "<img src=\"cards/6_of_diamonds.png\"/>",
"45" => "<img src=\"cards/7_of_diamonds.png\"/>",
"46" => "<img src=\"cards/8_of_diamonds.png\"/>",
"47" => "<img src=\"cards/9_of_diamonds.png\"/>",
"48" => "<img src=\"cards/10_of_diamonds.png\"/>",
"49" => "<img src=\"cards/jack_of_diamonds2.png\"/>",
"50" => "<img src=\"cards/queen_of_diamonds2.png\"/>",
"51" => "<img src=\"cards/king_of_diamonds2.png\"/>",
"52" => "<img src=\"cards/ace_of_diamonds.png\"/>"
);
你知道你可以實際使用的print_r如果你喜歡 - 你可以將其返回到您的代碼,而不是輸出緩衝器,喜歡的東西'$ aPrintedData =的print_r($ aVariable,真);' – CD001
不是'foreach($ fetch as $ card){}'按順序返回它們嗎? – Cyntech
會幫助我嗎?我假設它會創建一個相同的數組到我已有的'$ fetch' ..?另外,我在代碼中的print_r純粹是爲了調試。 – dan