這個簡單的代碼有什麼問題？

我想比較下面的2個數組，並找出差異。鍵「主人」和「公司」的值是不同的，但是當我比較這些數組時，它表示只有「公司」值是不同的。但是，當我創建2個只有一個鍵/值對「主人」的新陣列時，它可以正常工作。我犯了一些錯誤嗎？這個簡單的代碼有什麼問題？

<?php 

$arr1 = Array 
    (
     "leadid" => "418176000000069007", 
     "smownerid" => "418176000000047003", 
     "lead owner" => "Amit Patil", 
     "company" => "SAM", 
     "first name" => "Test", 
     "last name" =>"Lead1", 
     "designation" => "call", 
     "email" => "", 
     "phone" => "958", 
     "fax" => "", 
     "mobile" => "", 
     "website" => "www.infosys.con", 
     "lead source" => "Cold Call", 
     "lead status" => "Contact in Future", 
     "industry" => "None", 
     "no of employees" => "45000", 
     "annual revenue" => "0", 
     "rating" => "Active", 
     "smcreatorid" => "418176000000047003", 
     "created by" => "Amit Patil", 
     "modifiedby" => "418176000000047003", 
     "modified by" => "Amit Patil", 
     "created time" => "2012-04-05 19:58:00", 
     "modified time" => "2012-05-02 08:51:08", 
     "street" => "", 
     "city" => "", 
     "state" => "", 
     "zip code" => "", 
     "country" => "", 
     "description" => "", 
     "skype id" => "", 
     "email opt out" => "false", 
     "salutation" => "Mr.", 
     "secondary email" => "" 
     ); 

$arr2 = Array 
    (
     "leadid" => "418176000000069007", 
     "smownerid" => "418176000000047003", 
     "lead owner" => "Amit aaa", 
     "company" => "SAM A", 
     "first name" => "Test", 
     "last name" => "Lead1", 
     "designation" => "call", 
     "email" => "", 
     "phone" => "958", 
     "fax" => "", 
     "mobile" => "", 
     "website" => "www.infosys.con", 
     "lead_source" => "Cold Call", 
     "lead_status" => "Contact in Future", 
     "industry" => "None", 
     "no_of_employees" => "45000", 
     "annual_revenue" => "0", 
     "rating" => "Active", 
     "smcreatorid" => "418176000000047003", 
     "created_by" => "Amit Patil", 
     "modifiedby" => "418176000000047003", 
     "modified_by" => "Amit Patil", 
     "created_time" => "2012-04-05 19:58:00", 
     "modified_time" => "2012-05-02 08:51:08", 
     "street" => "", 
     "city" => "", 
     "state" => "", 
     "zip_code" => "0", 
     "country" => "", 
     "description" => "", 
     "skype_id" => "", 
     "email_opt_out" => "false", 
     "salutation" => "Mr.", 
     "secondary_email" => "" 
     ); 

$arr3 = array("lead owner" => "Amit Patil"); 
$arr4 = array("lead owner" => "Amit aaa"); 

print_r(array_diff($arr1,$arr2)); 
echo "<br>"; 
print_r(array_diff($arr3,$arr4)); 
?>

輸出是如下

Array ([company] => SAM) 
Array ([lead owner] => Amit Patil)

來源

2012-05-25 www.amitpatil.me

的輸出是什麼？ – AlphaMale

添加了輸出。 –

也添加了你想要的輸出。意味着你想要的輸出是什麼？ – AlphaMale

如果要在關聯數組之間進行區分，以便鍵值對非常重要，而不僅僅是值，請使用array_diff_assoc而不是array_diff。

來源

2012-05-25 05:31:39

它返回了一些錯誤的結果，我的意思是它返回的幾列不是不同的前綴：「no_of_employees」，「annual_revenue」，「created_by」「CREATED_TIME」。此鍵的值完全相同。爲什麼會這樣？ –

看起來你的一些鍵正在使用空格，有些使用下劃線。 –

嘗試複製上面的代碼...沒有下劃線。它也返回錯誤的結果。 –

你錯誤地理解它。

的array_diff文檔頁面說

返回包含所有從ARRAY1不在存在於任何其他陣列的條目的陣列。

但Amit Patil存在於第二陣列因此它返回只有一個值，它是在SAM和它只有一個值，它不存在於第二陣列。

來源

2012-05-25 05:30:55

Shakti，謝謝你的解釋，現在我明白了addta_diff（）和array_diff_assoc（）之間的差異 –

array_diff()返回互補值。所以你可以這樣做：

array_diff(array_merge($arr1, $arr2), array_intersect($arr1, $arr2));

這樣它會工作。

來源

2012-05-25 05:33:53

發生這種情況是因爲「array_diff」函數返回第一個數組中任何鍵的值，而不是第二個數組中的任何鍵都不會發生。

lead_owner「Amit Patil」不等於第二個數組lead_owner，但等於第二個數組的created_by和modified_by鍵。

您應該爲此使用「array_diff_assoc」。

來源

2012-05-25 05:35:26 jfoliveira

試試這個，看看，這應該工作

print_r(array_diff_assoc($arr1,$arr2)); 
echo "<br>"; 
print_r(array_diff_assoc($arr3,$arr4));

來源

2012-05-25 05:35:43 Wazan

這個簡單的代碼有什麼問題？

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