2011-02-26 51 views
0

我編寫了下面的代碼,但隨後提交了內部錯誤。我不知道發生了什麼問題。使用CURL將表單提交到Google表單

<?php 

//extract data from the post 
//extract($_GET) ; 
//set POST variables 

//The form https://spreadsheets.google.com/viewform?authkey=CJPbtZkI&hl=en&formkey=dEd5UFhRQ1ZfNzcwU1UwOVhIbF92cGc6MQ&ifq 
$url = 'https://spreadsheets.google.com/formResponse?authkey=CJPbtZkI&amp;hl=en&amp;formkey=dEd5UFhRQ1ZfNzcwU1UwOVhIbF92cGc6MQ&amp;ifq' ; 
$fields = array(
'pageNumber'=>urlencode("0") , 
'backupCache'=>urlencode("") , 
'submit'=>urlencode("Submit"), 
'entry.0.single'=>urlencode("") , 
'entry.1.single'=>urlencode("") , 
'entry.2.single'=>urlencode("") , 
'entry.3.single'=>urlencode("") , 
'entry.4.single'=>urlencode("") , 
'entry.5.single'=>urlencode("") , 
'entry.6.single'=>urlencode("") , 
'entry.7.single'=>urlencode("") , 
'entry.8.single'=>urlencode("") , 
'entry.9.single'=>urlencode("") , 
'entry.10.single'=>urlencode("") , 
'entry.11.single'=>urlencode(""), 
'entry.12.single'=>urlencode("") 
); 
//url-ify the data for the POST 
foreach($fields as $key=>$value) { $fields_string .= $key.'='.$value.'&' ; } 
rtrim($fields_string ,'&') ; 
//open connection 
$ch = curl_init() ; 
//set the url, number of POST vars, POST data 
curl_setopt($ch, CURLOPT_URL,$url) ; 
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: text/xml','Accept-Charset: UTF-8')); 
curl_setopt($ch, CURLOPT_POST, 1); 
curl_setopt($ch, CURLOPT_POSTFIELDS,$fields_string) ; 
//execute post 
$result = curl_exec($ch) ; 
print_r($fields_string); 
//close connection 
curl_close($ch) ; 

?> 
+0

嗨,我正在做同樣的事情,我的工作仍然不起作用,如果可以,請你幫忙嗎?我可以在哪裏向你發送代碼? – serdarsenay

回答

1

明顯的第一個問題是,你要使用的URL是HTML編碼(例如,它具有&amp;&

+0

它現在的作品!謝謝 – benone

0

嘗試添加:

curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false); 
0

挑剔點,但你的$field_strings變量仍然有尾隨符號。你需要這樣做:

$fields_string = rtrim($fields_string ,'&') ;