我創建一個日曆的招待所馬平ID和日期。它只是告訴預訂日期或可用日期。 綠色爲Available和Red爲已預訂。日曆腳本 - 在日期列
所有工作不錯,但我想使它變爲可編輯手段入住時間應該有一個鏈接「的書,它」和預訂日期應該有一個鏈接「未登記」。
我的劇本實際上是取出由表和店鋪ID和日期在數組(只有在該表中這兩列BTW)。然後使用in_arrary函數,它只是使所有在表中找到的日期變爲紅色,並將所有其他日期保留爲綠色。
我面臨的困難映射或填充ID和日期值有人能幫助我。
概括地說,我想ID和日期值的日期欄打印,所以我可以做鏈接。對於預訂日期,ID應傳遞到下一頁,以便我可以將其刪除並重新提供。而對於可用的日期,日期應該在下一頁傳遞,所以我在表中添加該日期並使其成爲預訂。
從大師們的幫助。
這裏是我完整的腳本:
<?php
error_reporting(0);
include("config.php");
/// get current month and year and store them in $cMonth and $cYear variables
(intval($_REQUEST["month"])>0) ? $cMonth = $_REQUEST["month"] : $cMonth = date("n");
(intval($_REQUEST["year"])>0) ? $cYear = $_REQUEST["year"] : $cYear = date("Y");
if ($cMonth<10) $cMonth = '0'.$cMonth;
// generate an array with all unavailable dates
$sql = "SELECT * FROM ".$SETTINGS["data_table"]." WHERE `date` LIKE '".$cYear."-".$cMonth."-%'";
$sql_result = mysql_query ($sql, $connection) or die ('request "Could not execute SQL query" '.$sql);
while ($row = mysql_fetch_assoc($sql_result)) {
$unavailable[] = $row["date"];
}
// calculate next and prev month and year used for next/prev month navigation links and store them in respective variables
$prev_year = $cYear;
$next_year = $cYear;
$prev_month = intval($cMonth)-1;
$next_month = intval($cMonth)+1;
// if current month is Decembe or January month navigation links have to be updated to point to next/prev years
if ($cMonth == 12) {
$next_month = 1;
$next_year = $cYear + 1;
} elseif ($cMonth == 1) {
$prev_month = 12;
$prev_year = $cYear - 1;
}
?>
<table style="width:100%; text-align: center;">
<tr>
<td class="mNav"><a href="javascript:LoadMonth('<?php echo $prev_month; ?>', '<?php echo $prev_year; ?>')"><< Prev</a></td>
<td colspan="5" class="cMonth"><?php echo date("F, Y",strtotime($cYear."-".$cMonth."-01")); ?></td>
<td class="mNav"><a href="javascript:LoadMonth('<?php echo $next_month; ?>', '<?php echo $next_year; ?>')">Next >></a></td>
</tr>
<tr>
<td style="width:16%;" class="wDays">M</td>
<td style="width:14%;" class="wDays">T</td>
<td style="width:14%;" class="wDays">W</td>
<td style="width:14%;" class="wDays">T</td>
<td style="width:14%;" class="wDays">F</td>
<td style="width:14%;" class="wDays">S</td>
<td style="width:14%;" class="wDays">S</td>
</tr>
<?php
$first_day_timestamp = mktime(0,0,0,$cMonth,1,$cYear); // time stamp for first day of the month used to calculate
$maxday = date("t",$first_day_timestamp); // number of days in current month
$thismonth = getdate($first_day_timestamp); // find out which day of the week the first date of the month is
$startday = $thismonth['wday'] ; // 0 is for Sunday and as we want week to start on Mon we subtract 1
if (!$thismonth['wday']) $startday = 7;
for ($i=1; $i<($maxday+$startday); $i++) {
if (($i % 7) == 1) echo "<tr>";
if ($i < $startday) { echo "<td> </td>"; continue; };
$current_day = $i - $startday + 1;
(in_array($cYear."-".$cMonth."-".$current_day,$unavailable)) ? $css='booked' : $css='available'; // set css class name based on date availability
if ($css == 'booked') {
echo "<td class='".$css."'>". $current_day . "<br/>" . "Booked" . "</td>";
}
elseif ($css == 'available') {
echo "<td class='".$css."'>". $current_day . "<br/>" . "Available" . "</td>";
}
if (($i % 7) == 0) echo "</tr>";
}
?>
</table>
嗨肖恩,感謝您的解決方案RESO大部分問題都存在,現在可用的日期顯示正確的Book Book鏈接,並在日後參數中使用正確的日期。但問題出現在已經在表格中的日期意味着預訂日期。現在應用您的解決方案後,只有一個日期列以紅色顯示,鏈接Unbook,但沒有參數中的ID。我認爲應該做一些小小的調整,讓它變得完美,請你幫忙。 – WebDeem
順便說一句,我現在有3個ID表,id = 1 date = 2014-02-21,id = 2 date = 2014-02-15,id = 3 date = 2014-02-16。它看起來像它沒有得到id值 – WebDeem
當我打印數組$美元[$行[「ID」]] = $行[「日期」];它只顯示最後一個日期2014-02-16其中有ID 3. – WebDeem