執行輸出參數SQL服務器

Question

我有三個參數@code是table1.column1任何元件，@date是元件table2.column2的日期和@total將是示出了出現在元件table2.column2時代的輸出參數。

我想執行一個程序，顯示table1.column1和table2.column1與date_column之間的內部連接;只有在參數@date之前的日期。

而且還@total

create procedure pro1 
    @code int, 
    @date datetime, 
    @total smallint OUTPUT 
as 
    select 
     table1.column1, table2.date_column 
    from 
     table1 
    inner join 
     table2 on table1.column1 = table2.column2 
    where 
     table1.column1 = @code 
     and table2.date_column = @date 
     and @date <= table2.date_column 

Answer 1

如果我正確的讀了你，@total就是返回的行數。如果確實如此，那麼您可以消除重複查詢的必要（並且必須處理併發問題，例如在查詢之間修改數據）：

create procedure pro1 
(
    @code int, @date datetime, @total smallint OUTPUT 
) 
as 
begin 
select 
    table1.column1, 
    table2.date_column 
from 
    table1 
    inner join 
    table2 on table1.column1 = table2.column2 
where 
    table1.column1 = @code 
    and 
    table2.date_column = @date 
    and 
    @date <= table2.date_column; 

set @total = @@rowcount; 
end 

Answer 2

返回的行選擇和在SQL Server中，在SELECT語句中你不能賦值給一個變量，並返回數據，因此，你需要兩次執行這個查詢，一次返回您期待回來的數據，一次爲@Total參數賦值。

create procedure pro1 
    @code int 
,@date datetime 
,@total int OUTPUT 
AS 
BEGIN 
    SET NOCOUNT ON; 
select table1.column1 
    , table2.date_column 
from table1 
inner join table2 on table1.column1 = table2.column2 
where table1.column1 = @code 
    and CAST(table2.date_column AS DATE) = @date 
    and table2.date_column <= @date 

select @total = SUM(table1.column1) 
from table1 
inner join table2 on table1.column1 = table2.column2 
where table1.column1 = @code 
    and CAST(table2.date_column AS DATE) = @date 
    and table2.date_column <= @date 

END