如何在PHP中訪問.json數據？

Question

我有一個.json文件。我想在我的.php文件中訪問這些數據。我有一個變量$ spellId，例如：$ spellId =「SummonerBarrier」;

我想通過使用$ spellId從.json文件獲取「名稱」。 任何想法我可以做到這一點？

我知道這裏有很多這樣的問題，但我不知道如何用我的代碼製作解決方案。

{ 
    "type": "summoner", 
    "version": "6.3.1", 
    "data": { 
     "SummonerBarrier": { 
      "id": "SummonerBarrier", 
      "name": "Barrier", 
      "description": "Shields your champion for 115-455 (depending on champion level) for 2 seconds.", 
      "tooltip": "Temporarily shields {{ f1 }} damage from your champion for 2 seconds.", 
      "maxrank": 1, 
      "cooldown": [ 
       210 
      ] 
     }, 
     "SummonerBoost": { 
      "id": "SummonerBoost", 
      "name": "Cleanse", 
      "description": "Remove..." 
     } 
    } 
} 

Answer 1

試試這個：

$data = '{ 
    "type": "summoner", 
    "version": "6.3.1", 
    "data": { 
     "SummonerBarrier": { 
      "id": "SummonerBarrier", 
      "name": "Barrier", 
      "description": "Shields your champion for 115-455 (depending on champion level) for 2 seconds.", 
      "tooltip": "Temporarily shields {{ f1 }} damage from your champion for 2 seconds.", 
      "maxrank": 1, 
      "cooldown": [ 
       210 
      ] 
     }, 
     "SummonerBoost": { 
      "id": "SummonerBoost", 
      "name": "Cleanse", 
      "description": "Remove..." 
     } 
    } 
}'; 

$decoded = json_decode($data); 
var_dump($decoded->data->SummonerBarrier->name); 

Answer 2

$array = json_decode($json, true); 

foreach ($array['data'] as $key => $value) { 
    echo "$key:$value[name]<br />"; 
} 

Answer 3

$decodeData = json_decode($data); 
$spellId="SummonerBarrier"; 
$nameToFetch=$decodeData->data->$spellId->name;