如何從兩個表中獲取特定數據？

Question

我具有以下表
評論表：

id user_id question_id comment 
1  2  3   hii 

用戶表：

id u_name user_image 
2  naveen  a.jpg 

當question_id = 3被選擇如何打印這樣的值

：

user_image  u_name comment 
a.jpg   naveen  hii <br> 

sql查詢：

$sql = "SELECT u.user_image, u.name, c.comment 
FROM users u INNER JOIN comment c 
    ON u.id = c.user_id 
WHERE c.question_id = 2"; 

$result = mysqli_query($conn, $sql); 
if (mysqli_num_rows($result) > 0) { 
    // output data of each row 
while($rows = mysqli_fetch_assoc($result)) { 
echo '<td class="small">'.$rows['name'].'</td>'; 
echo '<td class="small">'.$rows['user_image'].'</td>'; 
echo '<td class="small">'.$rows['comment'].'</td>'; 

} 
} 
else { 
    echo "0 results"; 
} 

Answer 1

使用的INNER JOIN：

SELECT u.user_image, u.u_name, c.comment 
FROM users u INNER JOIN comments c 
    ON u.id = c.user_id 
WHERE c.question_id = 3 

SQLFiddle