如果我理解正確,給定X軸上的縮放範圍,則還想縮放Y軸上的相同範圍。如果是這樣,你可以這樣做:
void chart1_SelectionRangeChanged(object sender, CursorEventArgs e)
{
// Given the visible (zoomed) range on X,
// it zooms the same relative range on Y:
// i.e. if on the X axis, the range 5% - 30% is zoomed,
// it zooms the same range on Y.
var axisY = this.chart1.ChartAreas[0].AxisY;
var totalXRange = e.Axis.Maximum - e.Axis.Minimum;
var totalYRange = axisY.Maximum - axisY.Minimum;
var ySelectionStart = (e.Axis.ScaleView.ViewMinimum - e.Axis.Minimum) *
totalYRange/totalXRange;
var ySelectionEnd = (e.Axis.ScaleView.ViewMaximum - e.Axis.Minimum) *
totalYRange/totalXRange;
axisY.ScaleView.Zoom(ySelectionStart,ySelectionEnd);
}
正如你所說,該事件AxisValueChanged
不存在;您鏈接的帖子可能意味着(現有)事件AxisViewChanged。
顯然,您也可以使用AxisViewChanged
來達到您的目的,並且調整我的代碼以利用該事件不應該那麼困難。
隨意問是否需要什麼幫助;)
編輯:
我修改了代碼,解釋你的目標。以下代碼計算對應於縮放X範圍內點的最大值和最小值的Y範圍:
void chart1_SelectionRangeChanged(object sender, CursorEventArgs e)
{
var axisY = this.chart1.ChartAreas[0].AxisY;
var xRangeStart = e.Axis.ScaleView.ViewMinimum;
var xRangeEnd = e.Axis.ScaleView.ViewMaximum;
// compute the Y values for the points crossing the range edges
double? yRangeStart = null;
var pointBeforeRangeStart = this.chart1.Series[0].Points.FirstOrDefault(x => x.XValue <= xRangeStart);
var pointAfterRangeStart = this.chart1.Series[0].Points.FirstOrDefault(x => x.XValue > xRangeStart);
if (pointBeforeRangeStart != null && pointAfterRangeStart != null)
yRangeStart = Interpolate2Points(pointBeforeRangeStart, pointAfterRangeStart, xRangeStart);
double? yRangeEnd = null;
var pointBeforeRangeEnd = this.chart1.Series[0].Points.FirstOrDefault(x => x.XValue <= xRangeEnd);
var pointAfterRangeEnd = this.chart1.Series[0].Points.FirstOrDefault(x => x.XValue > xRangeEnd);
if (pointBeforeRangeEnd != null && pointAfterRangeEnd != null)
yRangeEnd = Interpolate2Points(pointBeforeRangeEnd, pointAfterRangeEnd, xRangeEnd);
var edgeValues = new[] { yRangeStart, yRangeEnd }.Where(x => x.HasValue).Select(x => x.Value);
// find the points inside the range
var valuesInRange = this.chart1.Series[0].Points
.Where(p => p.XValue >= xRangeStart && p.XValue <= xRangeEnd)
.Select(x => x.YValues[0]);
// find the minimum and maximum Y values
var values = valuesInRange.Concat(edgeValues);
double yMin;
double yMax;
if (values.Any())
{
yMin = values.Min();
yMax = values.Max();
}
else
{
yMin = this.chart1.Series[0].Points.Min(x => x.YValues[0]);
yMax = this.chart1.Series[0].Points.Max(x => x.YValues[0]);
}
// zoom Y-axis to [yMin - yMax]
axisY.ScaleView.Zoom(yMin, yMax);
}
// see: http://en.wikipedia.org/wiki/Linear_interpolation#Linear_interpolation_between_two_known_points
public static double Interpolate2Points(DataPoint p1, DataPoint p2, double x)
{
var x0 = p1.XValue;
var y0 = p1.YValues[0];
var x1 = p2.XValue;
var y1 = p2.YValues[0];
return y0 + ((x - x0) * y1 - (x - x0) * y0)/(x1 - x0);
}
完全像我解釋的那樣工作,我更新了一些解釋以使我的最終目標清晰。 Il personaly測試更多明天:)謝謝 – EKS 2012-04-17 20:30:57
@EKS:編輯以說明您的更改;) – digEmAll 2012-04-17 21:38:04