如何從MATLAB中的.txt文件中讀取特定的信息？

我有一個很長的文本文件是這樣的：如何從MATLAB中的.txt文件中讀取特定的信息？

I0927 11:33:18.534551 16932 solver.cpp:244]  Train net output #0: loss = 2.61145 (* 1 = 2.61145 loss) 
I0927 11:33:18.534620 16932 sgd_solver.cpp:106] Iteration 20, lr = 0.001 
I0927 11:33:33.221546 16932 solver.cpp:228] Iteration 40, loss = 0.573027 
I0927 11:33:33.221771 16932 solver.cpp:244]  Train net output #0: loss = 0.573027 (* 1 = 0.573027 loss) 
I0927 11:33:33.221851 16932 sgd_solver.cpp:106] Iteration 40, lr = 0.001 
I0927 11:33:47.883162 16932 solver.cpp:228] Iteration 60, loss = 0.852016 
I0927 11:33:47.884717 16932 solver.cpp:244]  Train net output #0: loss = 0.852016 (* 1 = 0.852016 loss) 
I0927 11:33:47.884812 16932 sgd_solver.cpp:106] Iteration 60, lr = 0.001 
I0927 11:34:02.543320 16932 solver.cpp:228] Iteration 80, loss = 0.385975 
I0927 11:34:02.543442 16932 solver.cpp:244]  Train net output #0: loss = 0.385975 (* 1 = 0.385975 loss) 
I0927 11:34:02.543514 16932 sgd_solver.cpp:106] Iteration 80, lr = 0.001 
I0927 11:34:17.297544 16932 solver.cpp:228] Iteration 100, loss = 0.526758 
I0927 11:34:17.297659 16932 solver.cpp:244]  Train net output #0: loss = 0.526758 (* 1 = 0.526758 loss) 
I0927 11:34:17.297722 16932 sgd_solver.cpp:106] Iteration 100, lr = 0.001 
I0927 11:34:31.962934 16932 solver.cpp:228] Iteration 120, loss = 0.792767

我想提取以下信息

[ Iteration, Train net output, lr ]

，並把它們在MATLAB細胞。

請問您能指導我如何做到這一點？

來源

2016-09-28 user6726469

您希望在輸出中使用的'Iteration'是來自'sgd_solver'或'solver'的''Iteration''。 'regexp'應該能夠處理這個，但是你可能需要多次運行它。 –

您可以逐行讀取文件。然後使用'strfind'查找關鍵字位置並相應地切斷字符串。例如，對於「Iteration」，查找關鍵字「Iteration」起始索引（i1），然後查找下一個逗號（i2）。然後你知道該值位於[i1 + 9：i2-1] –

下面是我如何從日誌中提取'Train net output'的例子。 https://regex101.com/r/uGus7S/1。你應該能夠很容易地修改這個表達式，然後在MATLAB中使用它。 –

正如Some Guy建議，你可以用regexp：

fid = fopen('log.txt','r'); 
output = {}; 
line = fgetl(fid); 
while ischar(line) 
    l1 = regexp(line, 'Iteration\s+(\d+),\s+loss\s+=\s+', 'tokens', 'once'); 
    if ~isempty(l1) 
     %// we got the first line of an iteration 
     line = fgetl(fid); 
     l2 = regexp(line, 'Train net output #0: loss = (\S+)', 'tokens', 'once'); 
     line = fgetl(fid); 
     l3 = regexp(line, 'Iteration \d+, lr = (\S+)', 'tokens', 'once'); 
     output{end+1} = [str2double(l1{1}), str2double(l2{1}), str2double(l3{1})]; 
    end 
    line = fgetl(fid); 
end; 
fclose(fid); 
output = vertcat(output{:});

順便說一句，你的朱古力知道$CAFFE_ROOT/tools/extra/parse_log.py效用？

來源

2016-09-28 14:19:51 Shai

而不是在while循環中執行'regexp'，你可以使用'fread'一次讀取所有的東西，並一次性使用'regexp'來獲得'[Iteration，Train net output，lr]'。像你這樣使用'regexp'沒有使用'strfind'的好處，事實上這更難理解。 –

我刪除了前兩個和你的日誌的最後一行，使其保持一致，這樣你在每次迭代這樣經過Train net output和sgd_solver .. lr =行：

I0927 11:33:33.221546 16932 solver.cpp:228] Iteration 40, loss = 0.573027 
I0927 11:33:33.221771 16932 solver.cpp:244]  Train net output #0: loss = 0.573027 (* 1 = 0.573027 loss) 
I0927 11:33:33.221851 16932 sgd_solver.cpp:106] Iteration 40, lr = 0.001 
I0927 11:33:47.883162 16932 solver.cpp:228] Iteration 60, loss = 0.852016 
I0927 11:33:47.884717 16932 solver.cpp:244]  Train net output #0: loss = 0.852016 (* 1 = 0.852016 loss) 
I0927 11:33:47.884812 16932 sgd_solver.cpp:106] Iteration 60, lr = 0.001 
I0927 11:34:02.543320 16932 solver.cpp:228] Iteration 80, loss = 0.385975 
I0927 11:34:02.543442 16932 solver.cpp:244]  Train net output #0: loss = 0.385975 (* 1 = 0.385975 loss) 
I0927 11:34:02.543514 16932 sgd_solver.cpp:106] Iteration 80, lr = 0.001 
I0927 11:34:17.297544 16932 solver.cpp:228] Iteration 100, loss = 0.526758 
I0927 11:34:17.297659 16932 solver.cpp:244]  Train net output #0: loss = 0.526758 (* 1 = 0.526758 loss) 
I0927 11:34:17.297722 16932 sgd_solver.cpp:106] Iteration 100, lr = 0.001

可以使用讀取該文件爲文本fileread，然後使用下面的代碼執行regexp：

txt = fileread('log.txt'); 
it = regexp(txt,'I0927.*solver.cpp:228]\sIteration\s(.*),.*','tokens','dotexceptnewline') 

it = 

    1×4 cell array 

    {1×1 cell} {1×1 cell} {1×1 cell} {1×1 cell} 

net_out = regexp(txt,'I0927.*solver.cpp:244]\s*Train\snet\soutput.*loss\s=\s(\S*).*','tokens','dotexceptnewline'); 
lr = regexp(txt,'I0927.*sgd_solver.cpp:106]\sIteration.*lr\s=\s(\S*)','tokens','dotexceptnewline');

輸出需要調理的一點點，然後才能將其轉換爲數字：

% Get outputs out of their cells 
it = [it{:}]'; 
net_out = [net_out{:}]'; 
lr = [lr{:}]'; 

sim_out = str2double([it net_out lr]);

來源

2016-09-28 19:12:03

如何從MATLAB中的.txt文件中讀取特定的信息？

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