1
Im新php
並想問關於上傳多個文件使用name="image[]"
。這裏是我的代碼:如何簡單多個文件上傳使用名稱=「圖像[]」
HTML
<form action="" method="post" enctype="multipart/form-data">
<input type="file" name="image[]" multiple="multiple"/>
<input type="submit" name="submit"/>
</form>
PHP
<?php
$table_name ="posts";
$_POST['submit'];
$title = $_POST['title'];
$cat_id = $_POST['cat_id'];
$date = date('Y-m-d', strtotime($_POST['date']));
$description = mysql_real_escape_string($_POST['description']);
$status = $_POST['status'];
$sql = "INSERT INTO $table_name (title,cat_id,date,description,status) VALUES ('$title','$cat_id','$date','$description','$status')";
$result = mysql_query($sql);
$sqlImage = mysql_fetch_array(mysql_query("SELECT id FROM $table_name ORDER BY id DESC "));
$parentId = $sqlImage['id'];
foreach ($_POST['image'] as $images) {
$resImage = mysql_query("INSERT INTO media (parent_id,image) VALUES ('$parentId','$images') ");
}
$_SESSION['add_content'] = true;
echo ' <script>location.href="'.$base_url.''.$table_name.'"</script>';
?>
哪有我輸入我的形象?
你想對圖像做什麼? – adamdehaven 2013-04-09 14:21:17
'$ _POST ['submit'];'本身?你爲什麼這樣做?你可以做你想做的事,只要執行'foreach($ _ FILES as $ file)',然後使用'$ file',就像你通常使用'$ _FILES ['image']'[This](http:// www .php.net/manual/en/reserved.variables.files.php#106608)可能會有所幫助。 – Jon 2013-04-09 14:22:08
變量'image'不是'$ _POST'類型,而是'$ _FILES' – silentw 2013-04-09 14:22:17