For loop with different inputs

Question

請看下面的代碼，讓我知道我沒有看到什麼。我已經嘗試了幾乎所有的東西，以使其工作，但還沒有。

在此先感謝您的時間和幫助。

for (double c = c1; c <= c2; c = c + i) 
{ 
    cout << "Enter the lowest temperature: " << endl; 
    cin >> c1; 
    cout << "Enter the highest temperature: " << endl; 
    cin >> c2; 
    cout << "Enter the desired increment in temperature: " << endl; 
    cin >> i; 

    f = ((9/5) * c) + 32; 

    cout << "When C is " << c << " degrees Celsius, the temperature in Fahrenheit will be: " << f << " degrees." << endl; 

    cin.get(); 
} 
return 0; 

}

Answer 1

你把代碼中的錯誤部分的輸入。

c1和c2可能從未在循環之前分配過，並且您的代碼中反映的邏輯似乎不符合您的意圖，因爲它每次都會更改循環限制。

此外，請注意使用9.0而不是9得到double結果，而不是一個整數。

查看完整示例https://ideone.com/Uj974z。

int main() { 

    double c1, c2, i, f; 

    cout << "Enter the lowest temperature: " << endl; 
    cin >> c1; 
    cout << "Enter the highest temperature: " << endl; 
    cin >> c2; 
    cout << "Enter the desired increment in temperature: " << endl; 
    cin >> i; 

    for (double c = c1; c <= c2; c = c + i) 
    { 
     f = ((9.0/5) * c) + 32; 
     cout << "When C is " << c << " degrees Celsius, the temperature in Fahrenheit will be: " << f << " degrees." << endl; 
    } 

    return 0; 
} 

Answer 2

問題是，9/5返回1.你應該寫9.0/5。