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我放棄了,我重寫了3次代碼,我找不到代碼中的問題...我已經做了很多複雜的數據庫,但我無法找到這個小東西有什麼問題......最後是代碼和錯誤。我不能把這個查詢工作...'mysql''phpmyadmin'
謝謝:)
create database whatgameshouldiplay;
use whatgameshouldiplay;
CREATE TABLE `randomgame` (
`nomejogo` varchar(100) NOT NULL,
PRIMARY KEY (`nomejogo`)
) ENGINE=InnoDB;
create table `estilos` (
`codestilo` int(100) NOT NULL AUTO_INCREMENT,
`estilo` varchar(100) NOT NULL,
PRIMARY KEY (`codestilo`)
) ENGINE=InnoDB;
Create table `gameEstilos`(
`nomejogo` varchar(100) NOT NULL,
`estilo` varchar(100) NOT NULL,
primary key(`nomejogo`,`estilo`),
FOREIGN KEY (`nomejogo`) REFERENCES `randomgame` (`nomejogo`) ON UPDATE NO ACTION ON DELETE CASCADE,
FOREIGN KEY (`estilo`) REFERENCES `estilos` (`estilo`) ON UPDATE NO ACTION ON DELETE CASCADE
) ENGINE=InnoDB;
錯誤 SQL查詢:
創建表gameEstilos
( nomejogo
VARCHAR(100)NOT NULL, estilo
VARCHAR(100)NOT NULL, 主鍵( nomejogo
,estilo
), FOREIGN KEY(nomejogo
)參考文獻randomgame
(nomejogo
)ON UPDATE NO ACTION ON DELETE CASCADE, 外鍵(estilo
)參考文獻estilos
(estilo
)ON UPDATE NO ACTION ON DELETE CASCADE )ENGINE = InnoDB的 MySQL表示:文件
'#' 1215 - 不能添加外鍵約束
但我需要codestilo被AUTO_INCREMENT,如果我使用它作爲外鍵作爲主要的estilos? – JoaoFRF
嗯,我昨天真的很困,謝謝你的幫助我設法得到我想要的東西:) – JoaoFRF