用htmlunit檢索結果頁面

Question

我試圖用HtmlUnit模擬一個搜索網站旅行票。目標是獲得搜索結果頁面。我的代碼返回搜索頁面（等待結果......）

下面是代碼：

public class TestHtmlUnit { 

public static void main(String[] args) throws Exception { 

    // Create and initialize WebClient object 
    WebClient webClient = new WebClient(BrowserVersion.FIREFOX_10); 
    webClient.setThrowExceptionOnScriptError(false); 
    webClient.setRefreshHandler(new RefreshHandler() { 
     public void handleRefresh(Page page, URL url, int arg) throws IOException { 
      System.out.println("handleRefresh"); 
     } 

    }); 

    // visit Yahoo Mail login page and get the Form object 
    HtmlPage page = (HtmlPage) webClient.getPage("http://www.voyages-sncf.com/"); 
    HtmlForm form = page.getFormByName("TrainTypeForm"); 

    // Enter login and passwd of 
    form.getInputByName("origin_city").setValueAttribute("paris"); 
    form.getInputByName("destination_city").setValueAttribute("marseille"); 
    form.getInputByName("outward_date").setValueAttribute("28/03/2013"); 


    // Click "Sign In" button/link 
    page = (HtmlPage) form.getInputByValue("Rechercher").click(); 





    // Print the newMessageCount to screen 
    //System.out.println("newMessageCount = " + newMessageCount); 

    // System.out.println(page.asHTML());      
    System.out.println(page.asText()); 
    } 
} 

Answer 1

你應該等待頁面後點擊加載

試試這個

webClient.waitForBackgroundJavaScript(1000); 

或

webClient.setAjaxController(new NicelyResynchronizingAjaxController()); 
      webClient.setAjaxController(new AjaxController(){ 
       @Override 
       public boolean processSynchron(HtmlPage page, WebRequest request, boolean async) 
       { 
        return true; 
       } 
      }); 

或

JavaScriptJobManager manager = page.getEnclosingWindow().getJobManager(); 
      while (manager.getJobCount() > 0) { 
       Thread.sleep(100); 
      }