JSon數組數組

Question

我想寫一個JSon文檔及其相關的xsd文件，以生成JAXB類，我不認爲如果我以正確的方式做它。 我想是這樣的結構：

team 
    -name="name" 
    -game="game" 
    -intarray 
     int 
     int 
     ... 
     int 
    -values 
     [int1, int2] 
     [int1, int2] 
     ... 
     [int1, int2] 
    -stringarrays 
     [string1, string2,...., stringn] 
     [string1, string2,...., stringn] 
     ... 
     [string1, string2,...., stringn] 

所以我寫了我的XSD和在JSON文件中的示例串試圖讀取它

example line: 
{"name": "Team 1", "game": "game", "intarray": [1, 2, 3, 4, 5, 6], "values": [[10,20], [10,80], [10,30], [10,60], [10,50], [10,30]], "stringarrays": [["Azione", "Azione"], ["Azione", "Azione"], ["Azione", "Azione"], ["Azione", "Azione"], ["Azione", "Azione"], ["Azione", "Azione"]]} 

，這是我的xsd

<?xml version="1.0" encoding="UTF-8"?> 
<schema xmlns="http://www.w3.org/2001/XMLSchema" targetNamespace="http://www.example.org/teams" xmlns:tns="http://www.example.org/teams" elementFormDefault="qualified"> 

<element name="team_list" type="tns:lista_team"></element> 

<complexType name="team"> 
    <sequence> 
     <element name="name" type="string"></element> 
     <element name="game" type="string"></element> 
     <element name="intarray" type="int" maxOccurs="unbounded" 
      minOccurs="0"> 
     </element> 
     <element name="values" type="tns:ivev"></element> 
     <element name="stringarrays" type="tns:arrays"></element> 
    </sequence> 
</complexType> 

<complexType name="ivev"> 
    <sequence> 
     <element name="couple" type="tns:ivev_couple" maxOccurs="unbounded" minOccurs="0"></element> 
    </sequence> 
</complexType> 

<complexType name="ivev_couple"> 
    <sequence> 
     <element name="ivev_element" type="int" maxOccurs="unbounded" minOccurs="1"></element> 
    </sequence> 
</complexType> 

<complexType name="moveset"> 
    <sequence> 
     <element name="mosse" type="string" maxOccurs="unbounded" minOccurs="0"></element> 
    </sequence> 
</complexType> 

<complexType name="arrays"> 
    <sequence> 
     <element name="stringarray" type="tns:moveset" maxOccurs="unbounded" minOccurs="0"></element> 
    </sequence> 
</complexType> 

<complexType name="lista_team"> 
    <sequence> 
     <element name="squadra" type="tns:team" maxOccurs="unbounded" minOccurs="0"></element> 
    </sequence> 
</complexType> 

日食總是告訴我，我有一個MalformedJson，我THI NK問題是使用JSON行，我認爲XSD幾乎是正確的，但我可能是錯的:)

寫入的JSON文檔看起來像這樣的代碼：

Gson gson = new Gson(); 
String json = gson.toJson(team); 

try 
{ 
    FileWriter gwriter = new FileWriter("c:\\file.json"); 
    gwriter.write(json); 
    gwriter.close(); 
} 
catch(Exception e) 
{ 
} 

將會產生這JSON文件：

{ 
    "nome":"team1", 
    "game":"game", 
    "intarray":[1,2], 
    "arrayofintarrays":{ 
    "couple":[] 
    }, 
    ‌​"arrayofstringarrays":{ 
    "mossearray":[] 
    } 
} 

這個JSON文件，然後讀取這樣的：

Team[] teams_loaded= null; 

try 
{ 
    Reader reader = new InputStreamReader(DexLoader.class.getClassLoader().getResourceAsStream("teams.tx‌​t")); 
    Gson gson = new GsonBuilder().create(); 
    JsonReader read = new JsonReader(reader); 
    teams_loaded = gson.fromJson(read, Team[].class); 
} 
catch(Exception c) 
{ 
    c.printStackTrace(); 
} 

謝謝！

Answer 1

您正在編寫一個Team的實例，然後嘗試將其讀取爲Team的數組。你的閱讀代碼應該是：

Team team = gson.fromJson(read, Team.class); 

Answer 2

看來，使用數組JSON元素在GSON中有點棘手。

Team[] teams_loaded= null  
teams_loaded = gson.fromJson(read, Team[].class) 

嘗試讀取如下所示的團隊陣列，而不是像這樣讀取文件。

@Test 
    public void testSampleGSON() { 
     String sample = "[{\"name\":\"Sharath\",\"age\":\"24\"},{\"name\":\"Sharath\",\"age\":\"24\"},{\"name\":\"Sharath\",\"age\":\"24\"},]"; 
     System.out.println(sample); 

     Gson gson = new Gson(); 
     Type t = new TypeToken<Person[]>() { 
     }.getType(); 
     Person[] pl = gson.fromJson(sample, t); 
     System.out.println(pl); 

     for (int i = 0; i < pl.length; i++) { 
      System.out.println(pl[i]); 
     } 
     String jsonString = gson.toJson(pl); 
     System.out.println(jsonString); 
    } 

類Person是與下面給出的相同包中的公共類。

public class Person { 
    String name; 
    String age; 

    public void setName(String name) { 
     this.name = name; 
    } 

    public String getName() { 
     return this.name; 
    } 

    public String getAge() { 
     return this.age; 
    } 

    public void setAge(String age) { 
     this.age = age; 
    } 

希望這會有所幫助。

public String toString() { 
     return "Name : " + name + " Age : " + age; 
    } 
}