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我想通過使用簡單的HTTP請求和Java中的GET方法從stackoverflow api獲取我的用戶信息。如何從HTTP請求中獲取正確的數據
此代碼我用了之前得到用GET方法的另一個HTTP沒有問題的數據:
URL obj;
StringBuffer response = new StringBuffer();
String url = "http://api.stackexchange.com/2.2/users?inname=HCarrasko&site=stackoverflow";
try {
obj = new URL(url);
HttpURLConnection con = (HttpURLConnection) obj.openConnection();
con.setRequestMethod("GET");
int responseCode = con.getResponseCode();
System.out.println("\nSending 'GET' request to URL : " + url);
System.out.println("Response Code : " + responseCode);
BufferedReader in = new BufferedReader(new InputStreamReader(con.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
System.out.println(response.toString());
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
但在這種情況下,我想起來了陌生的符號,當我打印response
變種,像這樣:
�mRM��0�+�N!���FZq�\�pD�z�:V���JX���M��̛yO^���뾽�g�5J&� �9�YW�%c`do���Y'��nKC38<A�&It�3��6a�,�,]���`/{�D����>6�Ɠ��{��7tF ��E��/����K���#_&�yI�a�v��uw}/�g�5����TkBTķ���U݊c���Q�y$���$�=ۈ��ñ���8f�<*�Amw�W�ـŻ��X$�>'*QN�?�<v�ݠ FH*��Ҏ5����ؔA�z��R��vK���"���@�1��ƭ5��0��R���z�ϗ/�������^?r��&�f��-�OO7���������Gy�B���Rxu�#:0�xͺ}�\�����
在此先感謝。
這是正確的! – jorrin
謝謝這是正確的方法:) – HCarrasko