4
我創造了這個的jsfiddle嵌套列表元素嵌套的JSON:http://jsfiddle.net/mfnxm/1/JSON和jQuery:創建一個從
我試圖創建這個JSON:
[{
"link":"/about",
"title":"About",
"nodes":[{
"link":"/staff",
"title":"Staff",
"nodes":[{
"link":"/heads",
"title":"Dept Heads"
},{
"link":"/support",
"title":"Support"
}]
},{
"link":"/location",
"title":"Location"
}]
},{
"link":"/contact",
"title":"Contact"
}]
從這個無序列表:
<div id="tree">
<ul class=".sortable">
<li><a href="/about">About</a>
<ul class=".sortable">
<li><a href="/staff">Staff</a>
<ul class=".sortable">
<li><a href="/heads">Dept Heads</a></li>
<li><a href="/support">Support</a></li>
</ul>
</li>
<li><a href="/location">Location</a></li>
</ul>
</li>
<li><a href="/contact">Contact</a></li>
</ul>
</div>
以下是目前爲止的JavaScript(borrowed from here) - 但它並沒有爲我創建節點元素:
var out = [];
function processOneLi(node) {
var aNode = node.children("a:first");
var retVal = {
"link": aNode.attr("href"),
"title": aNode.text()
};
node.find("> .sortable > li").each(function() {
if (!retVal.hasOwnProperty("nodes")) {
retVal.nodes = [];
}
retVal.nodes.push(processOneLi($(this)));
});
return retVal;
}
$("#tree ul").children("li").each(function() {
out.push(processOneLi($(this)));
});
// Do something with data
$('#d').text(JSON.stringify(out));
我錯過了什麼?謝謝!