從外部文件訪問功能bash

Question

這非常簡單，但由於我仍然是shell腳本中的新生代，我無法做到這一點。很簡單，我有一個菜單驅動的腳本，當用戶輸入他的選擇時，我循環使用case函數並執行選定的菜單。 Uptil現在我正在用相同的腳本編寫完整的代碼。現在我將代碼放在外部腳本的每個菜單選項中，並從那裏訪問代碼。因此，它是這樣的，

#!/bin/bash 
. course_func 
file=names.dat 
[ ! -f $file ] && > $file 
while true 
do 
clear 
echo ------------------------------------------ 
echo 1. Create a record 
echo 2. View Records 
echo 3. Search for records 
echo 4. Delete records that match a pattern 
echo ------------------------------------------ 
echo "Please enter your choice or enter (q) to quit: \c ";read choice 
case $choice in 
    1) 
    create() 
    echo Enter to continue; read junk 
    ;; 
     *) 
    clear 
    echo Wat nonsense enter properly 
    echo Enter to continue: ;read crap 
    ;; 
esac 
done 

然後，我創建，我寫的創建（）函數

代碼是在鏈路另一外部腳本，

create() 
{ 
    while true 
    do 
     echo Please enter the name: ;read name 
     echo Please enter your surname: ;read surname 
     echo Please enter the address: ;read add 
     echo Please enter the cell no.: ;read cell 
     if yesno Do you really wish to save the following data to file 
     then 
     echo $name:$surname:$add:$cell >> $file 
     clear 
     echo The record has been inserted :D 
     else 
     echo The record was not save 
     fi 
     if yesno Do you wish to enter another record 
     then 
     : 
     else 
     xit 
     fi 
    done 
} 

addRecord() 
{ 

} 

search() 
{ 

} 

delRecord() 
{ 

} 

，但我得到一個錯誤，

course_func: line 31: syntax error near unexpected token `}' 
course_func: line 31: `}' 
menu_driven: line 18: syntax error near unexpected token `echo' 
menu_driven: line 18: ` echo Enter to continue; read junk' 

31行是我在哪裏結束addRecord函數，它是空函數，f或其餘案件。我們可以在bash中沒有空的函數嗎？

Answer 1

函數不能爲空！

- Advanced Bash-Scripting Guide: Chapter 24. Functions

相反，嘗試：

addRecord() 
{ 
    return 
}