我的表是這樣的(np_capacity):如何使用MAX(日期時間)選擇行並獲取列的最小值?
id tower datetime capacity
---|----|---------------------|----------
1 | A | 2016-05-29 09:02:41 | 34676
2 | B | 2016-05-29 09:02:41 | 10736
5 | C | 2016-05-29 09:02:41 | 55664
3 | D | 2016-05-29 09:02:41 | 32622
4 | A | 2016-05-29 13:08:38 | 5474
6 | B | 2016-05-29 13:08:38 | 20692
7 | C | 2016-05-29 13:08:38 | 134802
8 | D | 2016-05-29 13:08:38 | 4754
我想選擇所有的最大日塔那麼對於那些塔我也想在表中的最小容量值。
結果將是:
id tower datetime capacity MinCapacity
---|----|---------------------|----------|-------------
4 | A | 2016-05-29 13:08:38 | 5474 | 5474
6 | B | 2016-05-29 13:08:38 | 20692 | 10736
7 | C | 2016-05-29 13:08:38 | 134802 | 55664
8 | D | 2016-05-29 13:08:38 | 4754 | 4754
什麼我是這樣的,但它並不總是給我正確的最小值。
SELECT npc.*, groupedcap.MinCapacity
FROM np_capacity npc
INNER JOIN
(SELECT tower, MAX(date) AS MaxDate
FROM np_capacity
GROUP BY tower) groupednpc
ON npc.tower = groupednpc.tower
INNER JOIN
(SELECT tower, MIN(capacity) AS MinCapacity
FROM np_capacity
GROUP BY tower) groupedcap
ON npc.tower = groupedcap.tower
AND npc.date = groupednpc.MaxDate
LEAST()如何? – Strawberry
'LEAST()'有什麼幫助? – sagi