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我想在JPQL中執行MySql查詢。
這裏是我的MySQL查詢當嘗試添加條件後,JPQL查詢發出異常
select * from test.employee order by DEG != 'm2',DEG;
其中test
是架構名稱,employee
是表名和DEG
包含字符串。 我在JPQL中寫了這個,並得到異常。
EntityManagerFactory emFactory = Persistence.createEntityManagerFactory("DBConnectionPU");
EntityManager em = emFactory.createEntityManager();
Query q = em.createQuery("SELECT em FROM Employee em ORDER BY em.deg != 'm2', em.deg");
List<Employee> list = q.getResultList();
例外:
Exception Description: Syntax error parsing [SELECT em FROM Employee em ORDER BY em.deg != 'm2', em.deg].
[36, 50] The order by item is not a valid expression.
at org.eclipse.persistence.internal.jpa.EntityManagerImpl.createQuery(EntityManagerImpl.java:1605)
at dbconnection.DBConnection.main(DBConnection.java:39)
Caused by: Exception [EclipseLink-0] (Eclipse Persistence Services - 2.5.2.v20140319-9ad6abd): org.eclipse.persistence.exceptions.JPQLException
Exception Description: Syntax error parsing [SELECT em FROM Employee em ORDER BY em.deg != 'm2', em.deg].
[36, 50] The order by item is not a valid expression.
at org.eclipse.persistence.internal.jpa.jpql.HermesParser.buildException(HermesParser.java:155)
at org.eclipse.persistence.internal.jpa.jpql.HermesParser.validate(HermesParser.java:334)
at org.eclipse.persistence.internal.jpa.jpql.HermesParser.populateQueryImp(HermesParser.java:278)
at org.eclipse.persistence.internal.jpa.jpql.HermesParser.buildQuery(HermesParser.java:163)
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.buildEJBQLDatabaseQuery(EJBQueryImpl.java:142)
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.buildEJBQLDatabaseQuery(EJBQueryImpl.java:116)
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.<init>(EJBQueryImpl.java:102)
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.<init>(EJBQueryImpl.java:86)
at org.eclipse.persistence.internal.jpa.EntityManagerImpl.createQuery(EntityManagerImpl.java:1603)
... 1 more
我試圖用這個條件查詢,它工作正常。在直接的JPQL查詢中有什麼問題?我錯過了什麼嗎?
謝謝!有用 !!背後有什麼理由? –
@FahimFerojeAlJami Emm,對不起,我曾經遇到過這個問題,有時會幫助我解決它,而不是研究它的原因。 – Blank