分析響應時間分明python

我有一個看起來像這樣的輸入文件，我想計算分鐘的響應時間。分析響應時間分明python

datapoint,time,transaction,PT,Responsetime,errorcode 
a06i0000003uNQOAA2,2013-09-26T19:15:55.873+0000,EditMode,57,109.877193,0 
a06i0000003uNQOAA2,2013-09-26T19:15:55.875+0000,Update,58,733.741379,0 
a06i0000003uNQOAA2,2013-09-26T19:15:55.875+0000,ViewObject,94,386.893617,0 
a06i0000003uNQOAA2,2013-09-26T19:16:25.889+0000,EditMode,110,109.209091,0 
a06i0000003uNQOAA2,2013-09-26T19:16:25.889+0000,Update,109,743.660550,0 
a06i0000003uNQOAA2,2013-09-26T19:16:25.890+0000,ViewObject,181,376.198895,0 
a06i0000003uNQOAA2,2013-09-26T19:16:55.904+0000,EditMode,162,109.080247,0 
a06i0000003uNQOAA2,2013-09-26T19:16:55.904+0000,Update,161,738.683230,0 
a06i0000003uNQOAA2,2013-09-26T19:16:55.904+0000,ViewObject,266,372.627820,0 
a06i0000003uNQOAA2,2013-09-26T19:17:25.918+0000,EditMode,212,108.580189,0 
a06i0000003uNQOAA2,2013-09-26T19:17:25.919+0000,Update,213,735.244131,0 
a06i0000003uNQOAA2,2013-09-26T19:17:25.919+0000,ViewObject,350,362.394286,0 
a06i0000003uNQOAA2,2013-09-26T19:17:55.933+0000,EditMode,263,107.954373,0 
a06i0000003uNQOAA2,2013-09-26T19:17:55.933+0000,Update,264,732.598485,0 
a06i0000003uNQOAA2,2013-09-26T19:17:55.934+0000,ViewObject,431,359.965197,0 
a06i0000003uNQOAA2,2013-09-26T19:18:25.947+0000,EditMode,314,107.815287,0 
a06i0000003uNQOAA2,2013-09-26T19:18:25.948+0000,Update,315,733.292063,0 
a06i0000003uNQOAA2,2013-09-26T19:18:25.948+0000,ViewObject,516,360.098837,0 
a06i0000003uNQOAA2,2013-09-26T19:18:55.961+0000,EditMode,368,107.559783,0 
a06i0000003uNQOAA2,2013-09-26T19:18:55.961+0000,Update,366,731.808743,0 
a06i0000003uNQOAA2,2013-09-26T19:18:55.962+0000,ViewObject,600,359.780000,0 
a06i0000003uNQOAA2,2013-09-26T19:19:25.975+0000,EditMode,418,107.406699,0 
a06i0000003uNQOAA2,2013-09-26T19:19:25.976+0000,Update,419,731.613365,0 
a06i0000003uNQOAA2,2013-09-26T19:19:25.976+0000,ViewObject,686,358.169096,0 
a06i0000003uNQOAA2,2013-09-26T19:19:55.989+0000,EditMode,470,107.265957,0 
a06i0000003uNQOAA2,2013-09-26T19:19:55.990+0000,Update,467,732.107066,0 
a06i0000003uNQOAA2,2013-09-26T19:19:55.990+0000,ViewObject,768,360.317708,0 
a06i0000003uNQOAA2,2013-09-26T19:20:26.003+0000,EditMode,521,107.149712,0 
a06i0000003uNQOAA2,2013-09-26T19:20:26.004+0000,Update,521,733.990403,0 
a06i0000003uNQOAA2,2013-09-26T19:20:26.004+0000,ViewObject,853,361.735053,0 
a06i0000003uNQOAA2,2013-09-26T19:20:56.018+0000,EditMode,572,107.117133,0 
a06i0000003uNQOAA2,2013-09-26T19:20:56.018+0000,Update,572,733.139860,0 
a06i0000003uNQOAA2,2013-09-26T19:20:56.018+0000,ViewObject,937,361.497332,0 
a06i0000003uNQOAA2,2013-09-26T19:21:26.032+0000,EditMode,623,106.855538,0 
a06i0000003uNQOAA2,2013-09-26T19:21:26.032+0000,Update,623,732.057785,0 
a06i0000003uNQOAA2,2013-09-26T19:21:26.032+0000,ViewObject,1020,361.191176,0 
a06i0000003uNQOAA2,2013-09-26T19:21:56.046+0000,EditMode,674,107.112760,0 
a06i0000003uNQOAA2,2013-09-26T19:21:56.046+0000,Update,674,731.721068,0 
a06i0000003uNQOAA2,2013-09-26T19:21:56.046+0000,ViewObject,1106,360.622966,0 
a06i0000003uNQOAA2,2013-09-26T19:22:26.059+0000,EditMode,724,107.041436,0

這是我想出來的程序，這是給我的整個響應時間，而不是每一分鐘的具體。不知道我哪裏錯了。任何指針將不勝感激。

import numpy as np 
from scipy import stats 

rtlist = [] 
reqpslist = [] 

newFile = open('100ulog.csv','r') 
FILE = newFile.readlines() 
newFile.close() 


for line in FILE: 
    newline1 = line.split(":") 
    newline2 = line.split(",") 
    min = newline1[1] 
    if newline1[1] == min: 
     rtlist.append(newline2[4]) 
     reqpslist.append(newline2[3]) 
     print rtlist 

    else: 
     rtlist[:] = [] 
     min = min+1

來源

2013-09-27 nicko

什麼是你想要的輸出這是真的* *不明確 –

另外，分配'NEWLINE1 [1]'來'min'然後驗證它們相等什麼與回事 –

我只是要繼續前進，猜測我認爲你想要什麼。如果你編輯你的問題，我會編輯我的答案。您希望以分鐘爲單位獲得響應時間。我們首先解析整個文件並獲得有趣的部分 - a）分鐘，b）PT，c）響應時間。

我們將使用re：

>>> import re 
>>> data = open('100ulog.csv','r').read() 
>>> lst = re.findall('.+?,.+?T\d+:(\d+):.+?,.+?,(\d+),(\d+\.\d+),', data) 
>>> # This will return a list of interesting tuples like: [('16', '181', '376.198895'),...]

現在我們可以做任何我們想做的事情。比方說，我們要建立一個字典，會議紀要是它的鑰匙，和值的PT和響應時間的元組（我們將使用collections.defaultdict爲：

>>> from collections import defaultdict 
>>> dic = defaultdict(list) 
>>> for item in lst: 
...  dic[int(item[0])].append(item[1:3])

編輯：

？例如：

>>> data 
'a06i0000003uNQOAA2,2013-09-26T19:15:55.873+0000,EditMode,57,109.877193,0\na06i0 
000003uNQOAA2,2013-09-26T19:15:55.875+0000,Update,58,733.741379,0\na06i0000003uN 
QOAA2,2013-09-26T19:15:55.875+0000,ViewObject,94,386.893617,0\na06i0000003uNQOAA 
2,2013-09-26T19:16:25.889+0000,EditMode,110,109.209091,0\na06i0000003uNQOAA2,201 
3-09-26T19:16:25.889+0000,Update,109,743.660550,0\na06i0000003uNQOAA2,2013-09-26 
T19:16:25.890+0000,ViewObject,181,376.198895,0\na06i0000003uNQOAA2,2013-09-26T19 
:16:55.904+0000,EditMode,162,109.080247,0\na06i0000003uNQOAA2,2013-09-26T19:16:5 
5.904+0000,Update,161,738.683230,0\na06i0000003uNQOAA2,2013-09-26T19:16:55.904+0 
000,ViewObject,266,372.627820,0\na06i0000003uNQOAA2,2013-09-26T19:17:25.918+0000 
,EditMode,212,108.580189,0\na06i0000003uNQOAA2,2013-09-26T19:17:25.919+0000,Upda 
te,213,735.244131,0\na06i0000003uNQOAA2,2013-09-26T19:17:25.919+0000,ViewObject, 
350,362.394286,0\na06i0000003uNQOAA2,2013-09-26T19:17:55.933+0000,EditMode,263,1 
07.954373,0\na06i0000003uNQOAA2,2013-09-26T19:17:55.933+0000,Update,264,732.5984 
85,0\na06i0000003uNQOAA2,2013-09-26T19:17:55.934+0000,ViewObject,431,359.965197, 
0\na06i0000003uNQOAA2,2013-09-26T19:18:25.947+0000,EditMode,314,107.815287,0\na0 
6i0000003uNQOAA2,2013-09-26T19:18:25.948+0000,Update,315,733.292063,0\na06i00000 
03uNQOAA2,2013-09-26T19:18:25.948+0000,ViewObject,516,360.098837,0\na06i0000003u 
NQOAA2,2013-09-26T19:18:55.961+0000,EditMode,368,107.559783,0\na06i0000003uNQOAA 
2,2013-09-26T19:18:55.961+0000,Update,366,731.808743,0\na06i0000003uNQOAA2,2013- 
09-26T19:18:55.962+0000,ViewObject,600,359.780000,0' 
>>> import re 
>>> from collections import defaultdict 
>>> lst = re.findall('.+?,.+?T\d+:(\d+):.+?,.+?,(\d+),(\d+\.\d+),', data) 
>>> dic = defaultdict(list) 
>>> for item in lst: 
...  dic[int(item[0])].append(item[1:3]) 
... 
>>> dic 
defaultdict(<type 'list'>, {16: [('110', '109.209091'), ('109', '743.660550'), (
'181', '376.198895'), ('162', '109.080247'), ('161', '738.683230'), ('266', '372 
.627820')], 17: [('212', '108.580189'), ('213', '735.244131'), ('350', '362.3942 
86'), ('263', '107.954373'), ('264', '732.598485'), ('431', '359.965197')], 18: 
[('314', '107.815287'), ('315', '733.292063'), ('516', '360.098837'), ('368', '1 
07.559783'), ('366', '731.808743'), ('600', '359.780000')], 15: [('57', '109.877 
193'), ('58', '733.741379'), ('94', '386.893617')]})

來源

2013-09-27 19:21:18

謝謝？答案。我想要一分鐘內發生的所有交易的響應時間。例如。在19:15:55，有3個交易，我想收集這些列表中的響應時間。之後我需要收集19:16:55的響應時間。抱歉，不清楚。 – nicko

那麼我的答案應該給你，在「分鐘」範圍內。這意味着所有在19年發生的交易：** 16 **，然後發生在19年的所有交易：** 17 **等等。'dic'將持有它們。試一試 –

對不起，有一個錯字，並增加了一個例子。一探究竟。 –

分析響應時間分明python

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