的Sql - 遍歷兩個表，總結根據病情

Question

我工作的一個項目（基於點）投注程序的值，如果需要SQL Server上創建一個存儲過程，執行以下操作：

• 如果用戶在團隊中投注並獲得正確結果，則總計3分;
• 總和1分，如果結果與用戶猜測的結果不同，但仍設法正確判斷球隊是否贏，輸或關聯 （即用戶對皇馬 - 巴塞羅那投注;用戶猜測2 - 1;結果1 - 0）;
• 如果用戶得到任何錯誤，他不會得到任何分數。

我一直在尋找一種方式來做到這一點，但我無法找出一種方法。 這可能是一個不好的問題，我們都必須從某個地方開始。 我想過循環，這在理論上是我需要做的，但我需要遍歷賭注表中的每一行，並將其值與遊戲表中每行的值進行比較。

如果你能幫助我，那會很棒。謝謝。

編輯：哦，拍攝。對不起，我正要添加表格，而我忘記了。那麼，在這裏，他們是：

-Bets表：

CREATE TABLE Bets(
    id_bet  NUMERIC(18,0) NOT NULL PRIMARY KEY 
    ,id_user  NUMERIC(18,0) 
    ,id_game  NUMERIC(18,0) 
    ,date   NUMERIC(8,0) 
    ,time   NUMERIC(4,0) 
    ,goals_home NUMERIC(18,0) 
    ,goals_visitor NUMERIC(18,0) 
); 
INSERT INTO Bets(id_bet,id_user,id_game,date,time,goals_home,goals_visitor) VALUES (1,1,4,20170614,1600,1,1); 
INSERT INTO Bets(id_bet,id_user,id_game,date,time,goals_home,goals_visitor) VALUES (2,1,3,20170614,1600,1,1); 
INSERT INTO Bets(id_bet,id_user,id_game,date,time,goals_home,goals_visitor) VALUES (3,7,3,20170614,1600,1,1); 
INSERT INTO Bets(id_bet,id_user,id_game,date,time,goals_home,goals_visitor) VALUES (4,7,4,20170614,1600,1,1); 

---

-games表：

CREATE TABLE Games(
    id_game   NUMERIC(18,0) NOT NULL PRIMARY KEY 
    ,num_game  NUMERIC(18,0) 
    ,id_club_home NUMERIC(18,0) 
    ,id_club_visitor NUMERIC(18,0) 
    ,id_competition NUMERIC(18,0) 
    ,goals_home  NUMERIC(18,0) 
    ,goals_visitor NUMERIC(18,0) 
    ,date   NUMERIC(8,0) 
    ,time   NUMERIC(4,0) 
); 
INSERT INTO Games(id_game,num_game,id_club_home,id_club_visitor,id_competition,goals_home,goals_visitor,date,time) VALUES (1,1,3,6,2,2,2,20170614,1700); 
INSERT INTO Games(id_game,num_game,id_club_home,id_club_visitor,id_competition,goals_home,goals_visitor,date,time) VALUES (3,2,4,3,2,1,3,20170614,1800); 
INSERT INTO Games(id_game,num_game,id_club_home,id_club_visitor,id_competition,goals_home,goals_visitor,date,time) VALUES (4,3,3,4,2,1,3,20170614,1800); 
INSERT INTO Games(id_game,num_game,id_club_home,id_club_visitor,id_competition,goals_home,goals_visitor,date,time) VALUES (5,4,6,3,2,2,3,20170614,1800); 
INSERT INTO Games(id_game,num_game,id_club_home,id_club_visitor,id_competition,goals_home,goals_visitor,date,time) VALUES (6,5,4,6,2,NULL,NULL,20170614,1600); 

---

-I've想這（和其他的方法，但沒不保存它們）：

CREATE PROCEDURE [dbo].[Count_Points] @valor AS INT OUTPUT 
AS 
BEGIN 
    SET NOCOUNT ON; 

    DECLARE @a AS INT 
    DECLARE @goals_home_bet AS NUMERIC(18, 0) = (
      SELECT Bets.goals_home 
      FROM Bets 
      INNER JOIN Games ON Bets.id_game = Games.id_game 
      ) 
    DECLARE @goals_visitor_bet AS NUMERIC(18, 0) = (
      SELECT Bets.goals_visitor 
      FROM Bets 
      INNER JOIN Games ON Bets.id_game = Games.id_game 
      ) 
    DECLARE @goals_home_games AS NUMERIC(18, 0) = (
      SELECT Games.goals_home 
      FROM Bets 
      INNER JOIN Games ON Bets.id_game = Games.id_game 
      ) 
    DECLARE @goals_visitor_games AS NUMERIC(18, 0) = (
      SELECT Games.goals_visitor 
      FROM Bets 
      INNER JOIN Games ON Bets.id_game = Games.id_joid_gamego 
      ) 

    SET @valor = 0 
    SET @a = 1 
    SET @valor = sum(@valor + 3) 

    WHILE (
      (
       SELECT max(id_bet) 
       FROM Bets 
       ) > @a 
      ) 
    BEGIN 
     SET @a += 1 
    END 
END 

它只是用於測試它是否工作（因此僅引用值3），但顯然我只能得到3的值。其他方式我也會得到3或者甚至是。

編輯2：我的解決方案（可能不是最有效的，但仍然）：從bit

CREATE PROCEDURE [dbo].[Calculate_Points] 
     @control as int output, 
     @points as int output, 
     @nickname varchar(50) 

AS 
BEGIN 

    SET NOCOUNT ON; 

    declare @cont numeric(18,0)=1 
    declare @cont1 numeric(18,0) 
    declare @id_user numeric(18,0)=(select num_user from Users where nickname=@nickname) 
    declare @id_game numeric(18,0) 
    declare @goals_home_bet numeric(18,0) 
    declare @goals_visitor_bet numeric(18,0) 
    declare @goals_home_game numeric(18,0) 
    declare @goals_visitor_game numeric(18,0) 
    set @points=0 


    while(@cont<=(select max(num_bet) from Bets)) 
    begin 
     if exists (select id_user from Bets where @id_user=id_user and num_bet=@cont) 
     begin 
      set @id_game=(select id_game from Bets where num_bet=@cont) 
      set @goals_home_bet=(select goals_home from Bets where num_bet=@cont) 
      set @goals_visitor_bet=(select goals_visitor from Bets where num_bet=@cont) 
      set @cont1=1 
      while(@cont1<(select max(id_game) from Games)) 
      begin 
       if(@id_game=(select id_game from Games where id_game =@cont1)) 
       begin 
        set @goals_home_game=(select goals_home from Games where num_game=@cont1) 
        set @goals_visitor_game=(select goals_visitor from Games where num_game=@cont1) 

        if(@goals_home_bet=@golos_casa_jogo and @golos_fora_aposta=@golos_fora_jogo) 
         set @pontos+=3 
        else if((@goals_home_bet>@goals_visitor_bet and @goals_home_game>@goals_visitor_game) or (@goals_home_bet<@goals_visitor_bet and @goals_home_game<@goals_visitor_bet) or (@goals_home_bet=@goals_visitor_bet and @goals_home_game=@goals_visitor_bet)) 
         set @points+=1 
       end 

       set @cont1+=1 
      end 
     end 
     set @cont+=1 
    end 

END 

Answer 1

切換到int爲自己的目標，然後嘗試這樣的事：

create view vUserPointsPerGame 
as 
select 
    id_user, bets.id_game, 
    case 
     -- you could also just compare the goal differences if you want 
     when bets.goals_home = games.goals_home and bets.goals_visitor = games.goals_visitor then 3 
     when (bets.goals_home >= bets.goals_visitor and games.goals_home >= games.goals_visitor) or (bets.goals_home < bets.goals_visitor and games.goals_home < games.goals_visitor) then 1   
     else 0 
    end as Points 
from 
    bets 
    join games on bets.id_game = games.id_game 

go 

create view vUserTotalPoints 
as 
    select id_user, sum(points) as TotalPoints 
    from vUserPointsPerGame 
    group by id_user 
go 

select * from vUserTotalPoints 

那會向用戶返回所有投注的總分。

您可以使其更高效，但這裏的主要想法是您不需要循環或存儲過程來完成您想要在此完成的任務。

編輯：你提到你想要一個過程，因爲它更容易消耗。這裏有一個，將獲得的總積分爲單個用戶：

create procedure spGetUserTotalPoints 
(
    @iUserId int, 
    @oTotalPoints int output 
) 
as 
begin 
    select @oTotalPoints = TotalPoints 
    from vUserTotalPoints 
    where id_user = @iUserId 
end 

而且這裏的另一個，將獲得的總積分爲每個用戶對所有已知用戶：

create procedure spGetUsersTotalPoints 
as 
begin 
    select id_user, TotalPoints 
    from vUserTotalPoints 
end 

同樣，如果你是獲取有關批次的錯誤，只需按照每個語句執行一次，而不是依賴關鍵字go。一些SQL前端不喜歡那樣。