散裝搜索/替換使用python

Question

文件名我有：

1. Excel文件爲A1：B2。
2. 一個包含200個jpeg文件的文件夾。

我試圖與價值搜索文件名的文件夾中Column A如果發現不改變文件的擴展名的文件夾中，在Column B值替換它。

在這裏，我堅持使用各種打滑來做到這一點，但失敗了。這裏是我的代碼：

import os 
import xlrd 
path = r'c:\users\c_thv\desktop\x.xls' 
#collect the files in fexceler 
path1 = r'c:\users\c_thv\desktop' 
data = [] 
for name in os.listdir(path1): 
    if os.path.isfile(os.path.join(path1, name)): 
    fileName, fileExtension = os.path.splitext(name) 
    if fileExtension == '.py': 
     data.append(fileName) 
#print data 
#collect the filenames for changing 
book = xlrd.open_workbook(path) 
sheet = book.sheet_by_index(0) 
cell = sheet.cell(0,0) 
cells = sheet.row_slice(rowx=0,start_colx=0,end_colx=2) 
excel = [] 
#collect the workable data in an list 
for cell in cells: 
    excel.append(cell) 
#print excel 
#compare list for matches 
for i,j in enumerate(excel): 
    if j in data[:]: 
    os.rename(excel[i],data[i]) 

Answer 1

嘗試print "Match found"後if j in data[:]:只是爲了檢查，如果條件是見過。我的猜測是沒有匹配，因爲列表data是python filemanes（if fileExtension == '.py'）上的完整列表，您正在尋找excel列表中的jpeg文件。 此外，old未定義。

編輯：

如果我理解正確的話，這將有助於：

import os, xlrd 

path = 'c:/users/c_thv/desktop' #path to jpg files 
path1 = 'c:/users/c_thv/desktop/x.xls' 

data =[] #list of jpg filenames in folder 

#lets create a filenames list without the jpg extension 
for name in os.listdir(path): 
    fileName, fileExtension = os.path.splitext(name) 
    if fileExtension =='.jpg': 
     data.append(fileName) 


#lets create a list of old filenames in the excel column a 

book = xlrd.open_workbook(path1) 
sheet = book.sheet_by_index(0) 
oldNames =[] 
for row in range(sheet.nrows): 
    oldNames.append(sheet.cell_value(row,0)) 


#lets create a list with the new names in column b 
newNames =[] 
for row in range(sheet.nrows): 
    newNames.append(sheet.cell_value(row,1)) 


#now create a dictionary with the old name in a and the corresponding new name in b 

fileNames = dict(zip(oldNames,newNames)) 

print fileNames 

#lastly rename your jpg files 

for f in data: 
    if f in fileNames.keys(): 
     os.rename(path+'/'+f+'.jpg', path+'/'+fileNames[f]+'.jpg')