我以前沒有用過json。當我使用json響應的eval函數比它給我 錯誤的']'錯誤。我的json如下json in javascript
[{"name":"154.jpg","size":620888,"type":"image\/jpeg","url":"\/active\/components\/com_mtree\/img\/listings\/o\/Tulips.jpg","thumbnail_url":"\/active\/components\/com_mtree\/img\/listings\/s\/Tulips.jpg","delete_url":"\/active\/components\/com_mtree\/img\/listings\/upload.php?file=Tulips.jpg","delete_type":"DELETE"}]
是這個json中的任何錯誤。在JavaScript中我使用這個
var myObject = eval('(' + data + ')');
你可以發佈你的代碼與實際調用eval在? – 2011-05-26 11:58:52
不,JSON示例沒有問題。請給出更多的上下文,即更大的示例,以及失敗的JavaScipt代碼。 – Tomalak 2011-05-26 12:00:56