在Yii2中查詢內部搜索功能

當添加收入或費用時，兩個條目在名爲TabGLEntry的表中完成（兩個條目具有最相似的值，但借記卡，信用卡都具有相同的憑證號）。我想要顯示TabGLEntry的值（每個憑單號只應顯示一個值）。所以這是我對這種情況下的SQL查詢在Yii2中查詢內部搜索功能

SELECT * 
FROM `tabGLEntry` 
GROUP BY `voucher_no`

當我試圖在我的數據庫它的工作原理。現在，來實現它在Yii2 我想這在查詢檢索模型（TabglentrySearch.php）

public function search_all($params) 
    { 
     //~ $query = TabGLEntry::find(); 
     $query = TabGLEntry::find()->groupBy(['voucher_no'])->all(); 

     $dataProvider = new ActiveDataProvider([ 
      'query' => $query, 
     ]); 

     $this->load($params); 

     if (!$this->validate()) { 
      // uncomment the following line if you do not want to return any records when validation fails 
      // $query->where('0=1'); 
      return $dataProvider; 
     } 

     $query->andFilterWhere([ 
      'id' => $this->id, 
      'creation' => $this->creation, 
      'modified' => $this->modified, 
      'voucher_category' => $this->voucher_category, 
      'credit' => $this->credit, 
      'transaction_date' => $this->transaction_date, 
      'clearance_date' => $this->clearance_date, 
      'debit' => $this->debit, 
      'posting_date' => $this->posting_date, 
      'payment_method_id' => $this->payment_method_id, 
      'reference_date' => $this->reference_date, 
      'is_editable' => $this->is_editable, 
      'created_by' => $this->created_by, 
      'created_at' => $this->created_at, 
      'updated_by' => $this->updated_by, 
      'updated_at' => $this->updated_at, 
      'is_deleted' => $this->is_deleted, 
     ]); 

     $query->andFilterWhere(['like', 'name', $this->name]) 
      ->andFilterWhere(['like', 'entity_name', $this->entity_name]) 
      ->andFilterWhere(['like', 'modified_by', $this->modified_by]) 
      ->andFilterWhere(['like', 'account', $this->account]) 
      ->andFilterWhere(['like', 'fiscal_year', $this->fiscal_year]) 
      ->andFilterWhere(['like', 'against_voucher', $this->against_voucher]) 
      ->andFilterWhere(['like', 'against_voucher_type', $this->against_voucher_type]) 
      ->andFilterWhere(['like', 'is_opening', $this->is_opening]) 
      ->andFilterWhere(['like', 'against', $this->against]) 
      ->andFilterWhere(['like', 'voucher_type', $this->voucher_type]) 
      ->andFilterWhere(['like', 'is_advance', $this->is_advance]) 
      ->andFilterWhere(['like', 'remarks', $this->remarks]) 
      ->andFilterWhere(['like', 'cost_center', $this->cost_center]) 
      ->andFilterWhere(['like', 'reference_no', $this->reference_no]) 
      ->andFilterWhere(['like', 'voucher_no', $this->voucher_no]); 

     return $dataProvider; 
    }

，現在我得到一個錯誤

PHP Fatal Error – yii\base\ErrorException 

Call to a member function andFilterWhere() on a non-object

來源

2015-10-29 Bloodhound

此表中是否有任何外鍵？如果你可以在這裏添加'model'代碼，那將會很好。 –

按照active record find api發現返回yii\db\ActiveQueryInterface實例，該實例可以通過在one()之前調用yii\db\ActiveQueryInterface中定義的方法進一步定製，或調用all()以返回填充的ActiveRecord實例。

所以刪除all()然後你可以添加過濾器。

來源

2015-10-29 08:21:18 BHoft

在Yii2中查詢內部搜索功能

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