Android中的登錄界面給出錯誤

Question

我想在android中創建一個簡單的登錄界面，但是當我嘗試運行連接時發生了錯誤。我不知道，爲什麼會發生這種情況？

這裏是我的代碼：

public class MainActivity extends Activity{ 

    String username,password; 

    HttpClient httpclient; 
    HttpPost httppost; 
    HttpResponse response; 
    HttpEntity httpentity; 
    ArrayList<NameValuePair> namevaluepairs; 


    EditText etUser,etPass; 
    Button bLogin; 

    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_main); 

     etUser=(EditText) findViewById(R.id.etUser); 
     etPass=(EditText) findViewById(R.id.etPass); 

     bLogin=(Button) findViewById(R.id.bSubmit); 
     bLogin.setOnClickListener(new OnClickListener() { 

      @Override 
      public void onClick(View v) { 
       httpclient=new DefaultHttpClient(); 
       httppost=new HttpPost("http://192.168.1.107/php_project/checking.php"); 

       username=etUser.getText().toString(); 
       password=etPass.getText().toString(); 

       try { 

        namevaluepairs=new ArrayList<NameValuePair>(); 

        namevaluepairs.add(new BasicNameValuePair(username, username)); 
        namevaluepairs.add(new BasicNameValuePair("password", password)); 

        httppost.setEntity(new UrlEncodedFormEntity(namevaluepairs)); 
        response=httpclient.execute(httppost); 
        if(response.getStatusLine().getStatusCode()==200){ 

         httpentity=response.getEntity(); 

         if(httpentity!=null){ 
          InputStream inputstream=httpentity.getContent(); 

          JSONObject jsonResponse=new JSONObject(convertStreamToString(inputstream)); 

          String retUser=jsonResponse.getString("user"); 
          String retPass=jsonResponse.getString("pass"); 

          if(username.equals(retUser) && password.equals(retPass)){ 
           SharedPreferences sp=getSharedPreferences("logindetails", 0); 
           SharedPreferences.Editor spedit=sp.edit(); 

           spedit.putString("user", username); 
           spedit.putString("pass", password); 

           spedit.commit(); 

           Toast.makeText(getApplicationContext(), "SUCCESS !", Toast.LENGTH_LONG).show(); 
          }else{ 
           Toast.makeText(getApplicationContext(), "Inavalid Login details", Toast.LENGTH_LONG).show(); 
          } 
         } 

        } 
       } catch (Exception e) { 
        e.printStackTrace(); 

        Toast.makeText(getApplicationContext(), "Connection error", Toast.LENGTH_LONG).show(); 
       }     
      } 
     }); 


    } 

    private static String convertStreamToString(InputStream is){ 

     BufferedReader reader=new BufferedReader(new InputStreamReader(is)); 
     StringBuilder sb=new StringBuilder(); 

     String line=null; 

     try { 
      while((line=reader.readLine())!=null){ 
       sb.append(line + "\n"); 
      } 
     } catch (IOException e) { 
      e.printStackTrace(); 
     }finally{ 
      try { 
       is.close(); 
      } catch (IOException e2) { 
       e2.printStackTrace(); 
      } 
     } 
     return sb.toString(); 


    } 
} 

任何一個可以幫助我解決這個問題.. 當我在模擬器中運行它，它給我敬酒消息，即「連接錯誤」 ...

我簡直不明白，爲什麼我不能讓它成爲登錄... ???

Answer 1

請問這樣的問題時，請添加什麼logcat。

看着IP我的猜測是你想使用10.0.2.2。

在這裏閱讀更多：http://developer.android.com/tools/devices/emulator.html#emulatornetworking

Answer 2

Check whether you have given Network Connection permission in manifest. 

<uses-permission android:name="android.permission.INTERNET" /> 
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />