DO自定義PHP數組？

-6

$original = Array(
0=>"03A ",//first "03", substr("04w",0,2)=="03" 
1=>"04a ",//first "04" of first "03" 
2=>"05b ", 
3=>"06c ", 
4=>"07d ", 

6=>"04w ",//second "04" of first "03" 
7=>"05x ", 
8=>"06y ", 
9=>"07z ", 

10=>"03B ",//second "03" 
11=>"04l ",//first "04" of second "03" //substr("04w",0,2)=="03" 
12=>"05m ", 
13=>"06n ", 
14=>"07o ", 

15=>"04l ",//second "04" of second "03" //substr("04l",0,2)=="03" 
16=>"05m ", 
17=>"06n ", 
18=>"07o " 
); 

echo '<pre>'; 
print_r($original); 
echo '</pre>'; 

function customize_array($original){ 
    $customized_array = array(); 
    foreach($original as $value) { 
     if(substr($value,0,2) == "03") { 
     // CHANGE 1 
     $save = $value;// saved "03" yo put in child too. 
     ++$r;//inc parent 
     $j = 0; // child 
     $customized_array[$r][$j] =$value; // create parent 
     } else { 
     if (($j % 4) > 0) $value .= $value; 
     // CHANGE 2 
     else if ($j && $j % 4 == 0) $value = $save.$value; 
     $customized_array[$r][floor($j/4)] .= $value; 
     ++$j;//inc child 
     } 
    } 
    return $customized_array; 
} 

$display_list = customize_array($original); 
echo '<pre>'; 
print_r($display_list); 
echo '</pre>';

OUTPUT：DO自定義PHP數組？

/* 

Array 
(
    [1] => Array 
     (
      [0] => 03A 04a 05b 05b 06c 06c 07d 07d 
      [1] => 03A 04w 05x 05x 06y 06y 07z 07z 
     ) 

    [2] => Array 
     (
      [0] => 03B 04l 05m 05m 06n 06n 07o 07o 
      [1] => 03B 04l 05m 05m 06n 06n 07o 07o 
     ) 

)

這裏每個人都具有的功能的任何想法得到這個結果。

/* 

    Array 
(
    [1] => Array 
     (
      [0] => 03A 04a 05b 06c 07d 
      [1] => 03A 04w 05x 06y 07z 
     ) 

    [2] => Array 
     (
      [0] => 03B 04l 05m 06n 07o 
      [1] => 03B 04l 05m 06n  07o 
     ) 

) 


*/

來源

2011-01-27 kn3l

http://stackoverflow.com/questions/4814431/how-create-multiple-array-from-an-array-and-concatenate-each-elments http://stackoverflow.com/questions/4807625/how-create多陣列陣列 – arnaud576875 2011-01-27 16:18:11

你想做什麼？這僅僅是從你的問題轉發嗎？ – 2011-01-27 16:20:10

新手代碼）... – pltvs 2011-01-27 16:24:35

兩個變化：

foreach($original as $value) { 
    if(substr($value,0,2) == "03") { 
     // CHANGE 1 
     $save = $value; 
     ++$r;//inc parent 
     $j = 0; // child 
     $move_level[$r][$j] =$value; 
    } else { 
     if (($j % 4) > 0) $value .= $value; 
     // CHANGE 2 
     else if ($j && $j % 4 == 0) $value = $save.$value; 
     $move_level[$r][floor($j/4)] .= $value; 
     ++$j;//inc child 
    } 
}

See it

來源

2011-01-27 16:28:33 codaddict

你可以做到這一點與array_slice和破滅：

$a1 = array_slice($original, 0, 5); 
$a2 = array_slice($original, 5, 4); 
$a3 = array_slice($original, 10, 5); 
$a4 = array_slice($original, 15, 4); 

$output = new Array(
    new Array(implode("",$a1), implode("",$a2)), 
    new Array(implode("",$a3), implode("",$a4)) 
);

您應該能夠在使用類似的代碼來此for循環，如果你想這樣做的一個動態數組

您

來源

2011-01-27 16:24:01 wajiw

你可以做的是修剪前面的3個字符，比如substr($val, 3);，並在03a之前過去。或者你想從數組索引0中得到前3個字符並將其替換爲索引1？如果多數民衆贊成的情況下做的，如：

$array[0] => Array 
    (
     [0] => 03A04a05b05b06c06c07d07d //yes "03A" here 
     [1] => 04w05x05x06y06y07z07z // no "03A" here 
    ) 

$array[1] => Array 
    (
     [0] => 03B04l05m05m06n06n07o07o //"03B" here 
     [1] => 04l05m05m06n06n07o07o // no "03B" here 
    ) 
$new_array = array(); 
foreach($array as $value) 
{ 
    $first = substr($value[0], 0, 3); 
    $new_array[] = array($value[0], $value[1]); 
} 

print_r($new_array);

結果：

Array 
(
    [0] => Array 
    (
     [0] => 03A04a05b05b06c06c07d07d //yes "03A" here 
     [1] => 03A04w05x05x06y06y07z07z //yes "03A" here 
    ) 

    [1] => Array 
    (
     [0] => 03B04l05m05m06n06n07o07o //"03B" here 
     [1] => 03B04l05m05m06n06n07o07o//"03B" here 
    ) 

)

我肯定有一個更好的方式，這是一個全球性的方式，我認爲

來源

2011-01-27 16:24:05

DO自定義PHP數組？

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