定製Spring啓動驅動器健康狀況

Question

當我從它返回UP的狀態我的春節，啓動應用程序訪問/健康端點：

{ 
    "status": "UP" 
} 

但我想自定義像這樣我的狀態：

{ 
    "status": "success" 
} 

我如何定製狀態？

Answer 1

見http://docs.spring.io/spring-boot/docs/current/reference/html/production-ready-endpoints.html

專門章節「編寫自定義的健康指標」

Answer 2

建立新的健康狀況建設者和返回。

Status

@JsonProperty("status") 
public String getCode() { 
    return this.code; 
} 

如果如果實施HealthIndicator

@Component 
public class HealthChecker implements HealthIndicator { 

    @Override 
    public Health health() { 
     // Do checks .. 
     // if no issues 
     return Health.status("success").build(); 
    } 
} 

延伸AbstractHealthIndicator

@Component 
public class HealthIndicator extends AbstractHealthIndicator { 

    @Override 
    protected void doHealthCheck(Builder builder) throws Exception { 
     builder.status("success").build(); 
    } 
} 

嚴重性順序

，使這項工作，你必須用success更換UP或之前UP

application.properties

management.health.status.order=DOWN, OUT_OF_SERVICE, UNKNOWN, success 

或

移動它更新狀態嚴重性順序

management.health.status.order=DOWN, OUT_OF_SERVICE, UNKNOWN, success, UP