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我剛開始使用Anorm並且偶然發現了一個奇怪的行爲。當我嘗試做到以下幾點:Scala Play Anorm:佔位符未被替換
val userTableName: String = "User"
SQL("INSERT INTO {userTableName} (email, forename, surname, refreshToken) VALUES ({email}, {forename}, {surname}, {refreshToken})")
.on("userTableName" -> userTableName,
"email"->email,
"forename"->forename,
"surname"->surname,
"refreshToken"->refreshToken).executeInsert()
我以下錯誤:
play.api.Application$$anon$1: Execution exception[[JdbcSQLException: Syntax error in SQL statement "INSERT INTO ?[*] (EMAIL, FORENAME, SURNAME, REFRESHTOKEN) VALUES (?, ?, ?, ?) "; expected "identifier"; SQL statement:
INSERT INTO ? (email, forename, surname, refreshToken) VALUES (?, ?, ?, ?) [42001-175]]]
at play.api.Application$class.handleError(Application.scala:296) ~[play_2.11-2.3.8.jar:2.3.8]
at play.api.DefaultApplication.handleError(Application.scala:402) [play_2.11-2.3.8.jar:2.3.8]
at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$14$$anonfun$apply$1.applyOrElse(PlayDefaultUpstreamHandler.scala:205) [play_2.11-2.3.8.jar:2.3.8]
at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$14$$anonfun$apply$1.applyOrElse(PlayDefaultUpstreamHandler.scala:202) [play_2.11-2.3.8.jar:2.3.8]
at scala.runtime.AbstractPartialFunction.apply(AbstractPartialFunction.scala:36) [scala-library-2.11.1.jar:na]
Caused by: org.h2.jdbc.JdbcSQLException: Syntax error in SQL statement "INSERT INTO ?[*] (EMAIL, FORENAME, SURNAME, REFRESHTOKEN) VALUES (?, ?, ?, ?) "; expected "identifier"; SQL statement:
INSERT INTO ? (email, forename, surname, refreshToken) VALUES (?, ?, ?, ?) [42001-175]
at org.h2.message.DbException.getJdbcSQLException(DbException.java:332) ~[h2-1.3.175.jar:1.3.175]
at org.h2.message.DbException.getSyntaxError(DbException.java:197) ~[h2-1.3.175.jar:1.3.175]
at org.h2.command.Parser.readIdentifierWithSchema(Parser.java:2926) ~[h2-1.3.175.jar:1.3.175]
at org.h2.command.Parser.readTableOrView(Parser.java:5049) ~[h2-1.3.175.jar:1.3.175]
at org.h2.command.Parser.parseInsert(Parser.java:995) ~[h2-1.3.175.jar:1.3.175]
如果我硬編碼表名
SQL("INSERT INTO User (email, forename, surname, refreshToken) VALUES ({email}, {forename}, {surname}, {refreshToken})")
.on("email"->email,
"forename"->forename,
"surname"->surname,
"refreshToken"->refreshToken).executeInsert()
它的工作原理。我解決了這個問題,但最好不要爲重構原因硬編碼表名。爲什麼我不能在這種情況下使用Anorm的動態映射功能?
您不能在預準備語句中使用表名,只能使用實際值。 –
[將模式名稱作爲變量傳遞給查詢的最佳方式]的可能重複(http://stackoverflow.com/questions/29028122/best-way-to-pass-the-schema-name-as-a-可變 - 一個查詢) – cchantep