得到迴應json from serlvet

Question

如何從servlet接收到JavaScript的JavaScript響應？我使用AJAX後把它傳遞給servlet

this my ajax code 

$.ajax({ 
      type: "POST", 
      url: "formDelegationServlet", 
      data: { 
       jsonfield: JSON.stringify(dataString) // look here! 
      }, 
      dataType: "json", 
      //if received a response from the server 
      success: function (response) { 
       //our country code was correct so we have some information to display 
       if (response.success === true) { 
        console.log("response" + response); 
        $("#kota_merchant").val(response.rows.kota_merchant_del); 
        $("#alamat_merchant").val(response.rows.alamat_merchant_del); 
        $("#province_merchant").append(response.rows.prov_merchant_del); 

       } 
       //display error message 
       else { 
        $("#ajaxResponse").html("<div><b>Merchant Name in Invalid!</b></div>"); 
       } 
      }, 
      //If there was no resonse from the server 
      error: function (jqXHR, textStatus, errorThrown) { 
       console.log("Something really bad happened " + textStatus); 
       $("#ajaxResponse").html(jqXHR.responseText); 
      } 
     }); 

這是我的servlet代碼

protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { 
    JSONArray array = new JSONArray(); 
       for (int i = 0; i < dataMerchant.size(); i++) { 
        JSONObject obj = new JSONObject(); 
        EntityMerchant entityMerchant = dataMerchant.get(i); 

        if (entityMerchant.getNamaMerchant() == null) { 
         obj.put("nama_merchant_del", ""); 
         obj.put("success", false); 
        } else { 
         obj.put("nama_merchant_del", entityMerchant.getNamaMerchant()); 
         obj.put("success", true); 
        } 
        if (entityMerchant.getAlamatMerchant() == null) { 
         obj.put("alamat_merchant_del", ""); 
        } else { 
         obj.put("alamat_merchant_del", entityMerchant.getAlamatMerchant()); 
        } 
        if (entityMerchant.getKota() == null) { 
         obj.put("kota_merchant_del", ""); 
        } else { 
         obj.put("kota_merchant_del", entityMerchant.getKota()); 
        } 
        if (entityMerchant.getProvinsi() == null) { 
         obj.put("prov_merchant_del", ""); 
        } else { 
         obj.put("prov_merchant_del", entityMerchant.getProvinsi()); 
        } 
        if (entityMerchant.getPassword() == null) { 
         obj.put("pas_merchant_del", ""); 
        } else { 
         obj.put("pas_merchant_del", entityMerchant.getPassword()); 
        } 
        array.add(obj); 

       } 
       em.close(); 
       JSONObject jsonobj = new JSONObject(); 
       jsonobj.put("rows", array); 
       out.print(jsonobj.toString()); 
} 

這是我的響應JSON

{"rows":[{"nama_merchant_del":"MAJU SUKSES OCEAN","success":true,"alamat_merchant_del":"JL. DIPONEGORO 
NO. 1B","kota_merchant_del":"JAKARTA PUSAT","prov_merchant_del":"DKI JAKARTA","pas_merchant_del":"0" 
}]} 

我已經嘗試過很多次，但我已經不成功。請幫忙！

Answer 1

第一內容類型，然後初始化您PrintWriter對象如下：

PrintWriter out = null;  
res.setContentType("application/json; charset=UTF-8"); 
out = res.getWriter();