我是新來的bash腳本。我想要逐行讀取包含表格的文件。在每一行我都想把值賦給變量。這基本上是我的代碼的格式:雖然循環錯誤:語法錯誤附近的意外令牌`完成'
#!/bin/bash
while IFS= read -r line; do
echo $a $b $c $d
#if statements…
done < test.txt
我得到這個錯誤:「雖然環錯誤:附近意外的標記語法錯誤'完成」」
任何想法是錯我的代碼?我試着查看與同一個錯誤有關的其他幾個問題,但我無法修復我的代碼。感謝您的幫助!
編輯:這是整個代碼。它可能有其他錯誤(我真的是一個初學者),但我希望它有幫助。
#!/bin/bash
experiment_database="/home/gperron/datasets/ENCODE_tables/final_tables/test_experiment_database.txt"
file_database="/home/gperron/datasets/ENCODE_tables/final_tables/test_file_database.txt"
EXPERIMENT=`cat $experiment_database | head -n $PBS_ARRAYID | tail -n 1 | cut -f1`
echo "EXPERIMENT #$PBS_ARRAYID: $EXPERIMENT"
while IFS= read -r line; do
echo $file_ID $experiment $target $biological_replicate $technical_replicate $read_number $url $fastq_file $genome
if [ "$experiment" == "$EXPERIMENT" ]; then
if [ $biological_replicate == 1 ]; then
if [ $technical_replicate == 1 ]; then
if [ $read_number == 1 ]; then
ID_111= $file_ID
fastq_111= $fastq_file
url_111= $url
echo "FASTQ file 111 ID: $ID_111"
echo "FASTQ file 111: $fastq_111"
echo "FASTQ file 111 url: $url_111"
elif [ $read_number == 2 ]; then
ID_112= $file_ID
fastq_112= $fastq_file
url_112= $url
echo "FASTQ file 112 ID: $ID_112"
echo "FASTQ file 112: $fastq_112"
echo "FASTQ file 112 url: $url_112"
fi
elif [ $technical_replicate == 2 ]; then
if [ $read_number == 1 ]; then
ID_121= $file_ID
fastq_121= $fastq_file
url_121= $url
echo "FASTQ file 121 ID: $ID_121"
echo "FASTQ file 121: $fastq_121"
echo "FASTQ file 121 url: $url_121"
elif [ $read_number == 2 ]; then
ID_122= $file_ID
fastq_122= $fastq_file
url_122= $url
echo "FASTQ file 122 ID: $ID_122"
echo "FASTQ file 122: $fastq_122"
echo "FASTQ file 122 url: $url_122"
fi
elif [ $biological_replicate == 2 ]; then
if [ $technical_replicate == 1 ]; then
if [ $read_number == 1 ]; then
ID_211= $file_ID
fastq_211= $fastq_file
url_211= $url
echo "FASTQ file 211 ID: $ID_211"
echo "FASTQ file 211: $fastq_211"
echo "FASTQ file 211 url: $url_211"
elif [ $read_number == 2 ]; then
ID_212= $file_ID
fastq_212= $fastq_file
url_212= $url
echo "FASTQ file 212 ID: $ID_212"
echo "FASTQ file 212: $fastq_212"
echo "FASTQ file 212 url: $url_212"
fi
elif [ $technical_replicate == 2 ]; then
if [ $read_number == 1 ]; then
ID_221= $file_ID
fastq_221= $fastq_file
url_221= $url
echo "FASTQ file 221 ID: $ID_221"
echo "FASTQ file 221: $fastq_221"
echo "FASTQ file 221 url: $url_221"
elif [ $read_number == 2 ]; then
ID_222= $file_ID
fastq_222= $fastq_file
url_222= $url
echo "FASTQ file 222 ID: $ID_222"
echo "FASTQ file 222: $fastq_222"
echo "FASTQ file 222 url: $url_222"
fi
fi
fi
fi
done < test_file_database.txt
請讓我知道,如果我得到任何澄清。
後循環的肉。你可能有一些未封閉的嵌套構造或不平衡的parens或東西。 –
我在您發佈的代碼中看不到任何錯誤。創建一個再現問題的最小示例,並將* exact *代碼複製並粘貼到您的問題中。 (您可能會在縮小測試用例的同時自己解決問題;在這種情況下,您可以刪除問題或發佈答案,具體取決於其他用戶是否有用。) –
您發佈的代碼顯然適用於-is –