我正在處理我的第一個android應用程序,並且嘗試實施振動器時出現問題。我想要做的是讓AlertDialog顯示一條消息,並且因爲用戶可能實際上並沒有在當時運行該應用程序,所以請發出警報並振動手機,直到他們關閉警報。首先,我沒有使用振動器就可以正常工作,然後當我使用振動器時,它停止了警報聲音,並且不再顯示AlertDialog。我發現我能夠通過在新線程中執行它來解決報警問題,但仍然沒有AlertDialog。所以我試着將振動器移動到一個新的主題,並沒有解決我的問題。所以我目前的問題是,手機會播放鬧鐘聲音和振動,但我告訴它顯示的AlertDialog永遠不會顯示。我怎樣才能讓所有這三樣東西一次起作用?這裏是我的代碼(刪除無關的部分)......Android應用程序,振動器不與AlertDialog一起工作
public class AlarmDisplayActivity extends Activity {
private MediaPlayer media;
private PowerManager.WakeLock lock;
private AlertDialog alert;
private Vibrator vibrator;
private Thread vibrateThread;
@Override
public void onCreate(Bundle savedInstanceState) {
setContentView(R.layout.alarmdisplay_screen);
PowerManager power = (PowerManager)getSystemService(Context.POWER_SERVICE);
lock = power.newWakeLock(PowerManager.FULL_WAKE_LOCK |
PowerManager.ACQUIRE_CAUSES_WAKEUP, "AlarmReceiverActivity");
alert = new AlertDialog.Builder(AlarmDisplayActivity.this).create();
vibrator = (Vibrator)getSystemService(Context.VIBRATOR_SERVICE);
vibrateThread = new VibrateThread();
lock.acquire();
alert.setCancelable(false);
alert.setButton("OK", new OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
media.stop();
vibrateThread.interrupt();
lock.release();
}// Ends onClick
}// Ends setButton
startAlarm(this);
vibrateThread.start();
alert.show();
}// Ends onCreate
private void startAlarm(final Context context) {
new Thread() {
public void run() {
Uri uri = RingtoneManager.getDefaultUri(RingtoneManager.TYPE_ALARM);
if(uri == null) {
uri = RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
if(uri == null)
uri = RingtoneManager.getDefaultUri(RingtoneManager.TYPE_ALARM);
}// Ends if
media = new MediaPlayer();
try{
media.setDataSource(context, uri);
final AudioManager audioManager = (AudioManager)context.getSystemService(Context.AUDIO_SERVICE);
if(audioManager.getStreamVolume(AudioManager.STREAM_ALARM) != 0) {
media.setAudioStreamType(AudioManager.STREAM_ALARM);
media.setLooping(true);
media.prepare();
media.start();
}// Ends if
}// Ends try
catch(Exception e){}
}// Ends run method
}.start();
}// Ends startAlarm method
class VibrateThread extends Thread {
public VibrateThread() {
super();
}
public void run() {
try {
long[] vibPattern = new long[] {0L,100L,250L,1000L,250L,500L};
vibrator.vibrate(vibPattern, 2);
}// Ends try
catch (Exception e) {}
}// Ends run method
}// Ends VibrateThread class
}// Ends AlarmDisplayActivity
那麼,他使用一個線程,所以它不會發生在UI線程中 –