PHP的str_replace函數不是雙引號

Question

人可以幫我工作，我需要轉換字符串： 下面是HTML代碼：

<p><img src="/images/blog//023.jpg" alt="sposi a venezia" width="910" height="620" data-src="salvatorefranco.com/images/blog//023.jpg"; /><img src="/images/blog//wedding-photographer-in-portofino.jpg" alt="sposi a venezia" width="910" height="620" data-src="salvatorefranco.com/images/blog//…; /></p> 


alt="" to 
alt="title image" 

我想：

$var = str_replace('alt=""', 'alt="'.$title_image.'"', $object); 

但不會工作。 謝謝 Salvatore

Answer 1

你可以這樣做：

$object='alt=""'; 
$title_image="test"; 
$var = str_replace('alt=""', 'alt="'.$title_image.'"', $object); 
echo $var; 

Answer 2

您的代碼應該正常工作。

<?php 

$object = '<p><img src="/images/blog/023.jpg" alt="" width="910" height="620" data-src="/images/blog/023.jpg" /><img src="/images/blog//wedding-photographer-in-portofino.jpg" alt="" width="910" height="620" data-src="/blog//wedding-photographer-in-portofino.jpg" /></p>'; 

$title_image = "title image"; 

echo $var = str_replace('alt=""', 'alt="'.$title_image.'"', $object); 

？>

輸出

<p><img src="/images/blog/023.jpg" alt="title image" width="910" height="620" data-src="/images/blog/023.jpg" /><img src="/images/blog//wedding-photographer-in-portofino.jpg" alt="title image" width="910" height="620" data-src="/blog//wedding-photographer-in-portofino.jpg" /></p>

Working Link

Answer 3

我們可以嘗試str_replace函數的功能來解決這個問題

$alt='alt=""' ; 
$var = str_replace("{$alt}", 'alt="title image"',"{$alt}"); 
echo $var;