如何把NSUserdefault的價值在URL

Question

我有這個網址NSURL *url = [NSURL URLWithString:@"http://site.com/ArcGIS/rest/services/POI_Data/MapServer/0/query?&where=ToegangsNr+%3D+5002&returnGeometry=true&outSR=4326&f=json"];

但我想用NSUserdefault _phonenumber改變字符串中的5002值。

我該怎麼做？

此功能的其他代碼是：

ASIHTTPRequest *_request = [ASIHTTPRequest requestWithURL:url]; 
__weak ASIHTTPRequest *request = _request; 

request.requestMethod = @"POST"; 
[request addRequestHeader:@"Content-Type" value:@"application/json"]; 
[request appendPostData:[json dataUsingEncoding:NSUTF8StringEncoding]]; 
// 5 
[request setDelegate:self]; 
[request setCompletionBlock:^{ 
    [MBProgressHUD hideHUDForView:self.view animated:YES]; 

    NSString *responseString = [request responseString]; 
    NSLog(@"Response: %@", responseString); 
    [self plotCrimePositions:request.responseData]; 

}]; 
[request setFailedBlock:^{ 
    [MBProgressHUD hideHUDForView:self.view animated:YES]; 
    NSError *error = [request error]; 
    NSLog(@"Error: %@", error.localizedDescription); 
}]; 

Answer 1

NSURL *url = [NSURL URLWithString:@"http://site.com/ArcGIS/rest/services/POI_Data/MapServer/0/query?&where=ToegangsNr+%3D+5002&returnGeometry=true&outSR=4326&f=json"]; 
NSString *urlString = [url absoluteString]; 
urlString = [urlString stringByReplacingOccurrencesOfString:@"5002" withString:[userDefaults objectForKey:@"_phoneNumber"]]; 
NSLog(@"%@",urlString); 
url = [NSURL URLWithString:urlString]; 
NSLog(@"%@",url); 

希望它能幫助。

Answer 2

試試這個：

NSString *urlStr = [NSString stringWithFormat:@"http://site.com/ArcGIS/rest/services/POI_Data/MapServer/0/query?&where=ToegangsNr+%%3D+%@&returnGeometry=true&outSR=4326&f=json", [[NSUserDefaults standardUserDefaults] objectForKey:@"_phonenumber"]]; 
NSURL* url = [NSURL URLWithString:urlStr];